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marysya [2.9K]
3 years ago
13

Solve square root X^2+12x+43=0

Mathematics
2 answers:
AlekseyPX3 years ago
5 0
x^2+12x+43=0
 

x= \dfrac{-b+ \sqrt{b^2-4ac} }{2a}, \dfrac{-b- \sqrt{b^2-4ac} }{2a} 

x= \dfrac{-12+ \sqrt{12^2-4*43} }{2},\dfrac{-12- \sqrt{12^2-4*43} }{2} 

x= \dfrac{-12+2 \sqrt{7i} }{2}, \dfrac{-12-2 \sqrt{7i} }{2} 

x=-6+ \sqrt{7i},-6- \sqrt{7i}
Novay_Z [31]3 years ago
5 0
X²+12x+43=0

This a quadratic equation ax²+bx+c=0 (in our case a=1, b=12, & c=43)

to solve it, means to calculate the value of x which render this equation nil

In short we have to find the roots x' & x'' by applying the following formula:

x' = [-b+√(b² - 4ac)] / 2a  & x" =[-b - √(b² - 4ac)] / 2a 
If you plug the related values you will notice the amount inside the radical (√)
is negative. As you know such an amount should be positif, hence their is no roots & consequently no solution

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9 Is −4x3 and 10 is −5a2
5 0
3 years ago
The teams ratio of games won to games played was 5 to 6. If the team played 36 games how many games did The team fail to win
alexdok [17]

Answer:

well this is simple 5x6= 30 and 6x6= 36 so its 30/6

Step-by-step explanation:

because we need to get 6 to 36 and we know that 6x6 then you also have to multiply 5x6 so then thats 30

5 0
2 years ago
The sum of the 6th and seventh terms in a sequence of 12 numbers with a common difference is 16. What is the Sum of the number s
patriot [66]

Answer:

96

Step-by-step explanation:

commom difference = d

a₆ + a₇ = 16

a₅ + a₈ = (a₆ - d) + (a₇ + d) = a₆ + a₇ = 16

a₄ + a₉ = (a₆ - 2d) + (a₇ + 2d) = a₆ + a₇ = 16

Similarly,

a₃ + a₁₀ = 16, a₂ + a₁₁ = 16, a₁ + a₁₂ = 16

so

a₁ + a₂ + ... + a₁₁ + a₁₂ = 6 x 16 = 96

6 0
2 years ago
What is a-5/6= -3 2/3 + 5/6
valentinak56 [21]

Answer:

A=-2

Step-by-step explanation:

iekdkdkdkdkdkdkdkdkkdd

3 0
3 years ago
The team mascot shoots a rolled T-shirt from a special T-shirt cannon to a section of people in the stands at a basketball game.
Svet_ta [14]
For this parabola we have:
f ( 0 ) = 8
and : f ( 1 ) = 24
In the first equation ( A) :
f ( 0 ) = - 16 * ( 0 - 1 )² + 24 = - 16 * 1 + 24 = 8 ( correct )
f ( 1 ) = - 16 * ( 1 - 1 )² + 24 = 24  ( correct )
For B:
f ( 0 ) = - 16 * ( 0 + 1 )² + 24 = - 16 + 24    = 8  ( correct )
f ( 1 ) = - 16 * ( 1 + 1 )² + 24 = - 16 * 4 + 24 = - 64 + 24 = 40 ( false )
For C:
f ( 0 ) = - 16 * ( 0 - 1 )² - 24 = - 16 - 24 = - 40 ( false )
f ( 1 ) = - 16 * ( 1 - 1 )² - 24 = - 24  ( false )
For D:
f ( 0 ) = - 16 * ( 0 + 1 )² - 24 = - 16 - 24 = - 40 ( false )
f ( 1 ) = - 16 * ( 1 - 1 )² - 24 = - 24   ( false )
Answer:
A )  f ( t ) =  - 16 * ( t - 1 )² + 24
   

6 0
3 years ago
Read 2 more answers
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