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kaheart [24]
2 years ago
11

__N2O5+__H2O->__HNO3 What's the reaction?

Chemistry
1 answer:
77julia77 [94]2 years ago
6 0

Answer:

N₂O₅ + H₂O --> 2HNO₃

This reaction is a combination reaction

Explanation:

I find that making a table is an easy way to balance a table. The table would be something like this:

Reactants (left) Products (right)

N = 2 N = 1

O = 6 O = 3

H = 2 H = 1

The number next the symbol represents how many of atoms of that particular element are present.

The aim is to make the number of atoms of each element on the left side to be equal to the number of atoms of each element on the right side. As we can see, there are 1 more nitrogen than on the right, 3 more oxygen than on the right and 1 more hydrogen than on the left.

So to make the numbers of atoms of each element on right equal to the number of atoms of each element on the left, we have to add a number. This number CANNOT be a subscript number because that would change the reaction.

We can add a 2 in front of the product (this is because there are less atoms in the right side of the equation).

N₂O₅ + H₂O --> 2HNO₃

This means there are now two HNO₃ molecules so every atom in this molecule is basically multiplied by 2. So 1 nitrogen atom becomes two (1 × 2 = 2), 3 oxygen atoms become 6 (3 × 2 = 6) and 1 hydrogen atom becomes 2 (1 × 2 = 2). If we were to make a table again with the following equation - N₂O₅ + H₂O --> 2HNO₃, the table would be as so:

Reactants (left) Products (right)

N = 2 N = 2

O = 6 O = 6

H = 2 H = 2

Now the equation is balanced as we can see the number each type of atom is the same on the right and left side.

You might be interested in
Which of the following best describes an empirical formula?
Monica [59]

Answer:

Option C :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

Explanation:

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

Tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

For Example

      C₂H₆O₂ Consist of  Carbon (C), Hydrogen (H), and Oxygen (O)

Now

Look at the ratio of these three atoms in the compound

                         C : H : O

                         2 : 6 : 2

Divide the ratio by two to get simplest ratio

                          C : H : O

                         2/2 : 6/2 : 2/2

                             1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

                     Empirical formula of C₂H₆O₂ = CH₃O

So, Option C is correct :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

6 0
3 years ago
Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,
7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 )   N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)  ; Kc = 1.54e - 31

2)   N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)  ; Kc = 2.16e - 24

   upon reversing  ( 2 )  equation

     N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)   Kc = 1/2.16e - 24  

    now adding 1 and reversed equation (2)

       N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)

      N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)

   we get ,

                  N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)  Kc = 1.54e-31 × 1/2.61e - 24

       equilibrium constant of equation (3) is -

            Kc = 1.54e - 31 / 2.61e - 24

3 0
2 years ago
A speed time graph shows that a car moves at 20 m/s for 15s. The car's speed steadily decreases until it comes to a stop at 40s.
ladessa [460]
0s to 15s: constant speed/zero acceleration
15s to 40s: constant gradient, therefore constant deceleration
4 0
2 years ago
Cdvshduejsnxhhwjxhxh ydujdbxg
fiasKO [112]

Answer:

This is not a question

Explanation:

5 0
3 years ago
Read 2 more answers
30 pts! Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liter
mihalych1998 [28]
First, calculate the number of moles of sodium present with the given mass,

              31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium

It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.

           mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
                  mols of H2 = 0.685 mols H2

Then, at STP, 1 mol of gas = 22.4 L.
                
                 volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
                     volume of H2 = 15.34 L

Answer: 15.34 L
3 0
3 years ago
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