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kaheart [24]
2 years ago
11

__N2O5+__H2O->__HNO3 What's the reaction?

Chemistry
1 answer:
77julia77 [94]2 years ago
6 0

Answer:

N₂O₅ + H₂O --> 2HNO₃

This reaction is a combination reaction

Explanation:

I find that making a table is an easy way to balance a table. The table would be something like this:

Reactants (left) Products (right)

N = 2 N = 1

O = 6 O = 3

H = 2 H = 1

The number next the symbol represents how many of atoms of that particular element are present.

The aim is to make the number of atoms of each element on the left side to be equal to the number of atoms of each element on the right side. As we can see, there are 1 more nitrogen than on the right, 3 more oxygen than on the right and 1 more hydrogen than on the left.

So to make the numbers of atoms of each element on right equal to the number of atoms of each element on the left, we have to add a number. This number CANNOT be a subscript number because that would change the reaction.

We can add a 2 in front of the product (this is because there are less atoms in the right side of the equation).

N₂O₅ + H₂O --> 2HNO₃

This means there are now two HNO₃ molecules so every atom in this molecule is basically multiplied by 2. So 1 nitrogen atom becomes two (1 × 2 = 2), 3 oxygen atoms become 6 (3 × 2 = 6) and 1 hydrogen atom becomes 2 (1 × 2 = 2). If we were to make a table again with the following equation - N₂O₅ + H₂O --> 2HNO₃, the table would be as so:

Reactants (left) Products (right)

N = 2 N = 2

O = 6 O = 6

H = 2 H = 2

Now the equation is balanced as we can see the number each type of atom is the same on the right and left side.

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Explanation:

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A is Ea, which stands for activating energy. Energy is needed to get the reaction underway and Ea is the energy needed to “start” the reaction.

B is the temperature either released or absorbed.

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2 years ago
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What is the mass of the solid NH4Cl formed when 75.5 g of NH3 is mixed with an equal mass of HCl? What is the volume of the gas
Gekata [30.6K]

Answer : The volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of NH_4Cl produced is, 110.7 grams.

Explanation :

The balanced chemical reaction will be:

NH_3+HCl\rightarrow NH_4Cl

First we have to calculate the moles of NH_3 and HCl

\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}

Molar mass of NH_3 = 17 g/mole

\text{Moles of }NH_3=\frac{75.5g}{17g/mole}=4.44mole

and,

\text{Moles of }HCl=\frac{\text{Mass of }HCl}{\text{Molar mass of }HCl}

Molar mass of HCl = 36.5 g/mole

\text{Moles of }HCl=\frac{75.5g}{36.5g/mole}=2.07mole

Now we have to calculate the limiting and excess reagent.

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of NH_3

So, 2.07 mole of HCl react with 2.07 mole of NH_3

From this we conclude that, NH_3 is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

The remaining moles of HCl gas = 4.44 - 2.07 = 2.37 moles

Now we have to calculate the volume of the gas remaining.

Using ideal gas equation :

PV = nRT

where,

P = Pressure of gas = 752 mmHg = 0.989 atm     (1 atm = 760 mmHg)

V = Volume of gas = ?

n = number of moles of gas = 2.37 moles

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 14.0^oC=273+14.0=287K

Putting values in above equation, we get:

0.989atm\times V=2.37mole\times (0.0821L.atm/mol.K)\times 287K

V = 56.5 L

Now we have to calculate the moles of NH_4Cl

As, 1 mole of HCl react with 1 mole of NH_4Cl

So, 2.07 mole of HCl react with 2.07 mole of NH_4Cl

Now we have to calculate the mass of NH_4Cl

\text{ Mass of }NH_4Cl=\text{ Moles of }NH_4Cl\times \text{ Molar mass of }NH_4Cl

Molar mass of NH_4Cl = 53.5 g/mole

\text{ Mass of }NH_4Cl=(2.07moles)\times (53.5g/mole)=110.7g

Thus, the volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of NH_4Cl produced is, 110.7 grams.

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