Answer:
The proofing is given below:
Step-by-step explanation:

Hence, it is proved
Answer:
12
Step-by-step explanation:
Given that
Current count of pushups = 8
Number of increase in pushups each day = 2
The desired pushup goal on daily basis = 30
Days require = x= ?
as we can conclude the number of pushups would increase by following sequence
8, 10, 12, 14, 16, ......30
Now as we can be the number of pushups by a constant number each day it means this sequence is arithmetic.
First term of our sequence is X1 and the final term is Xn, and the difference between two consecutive terms (Common Difference) is 2.
So
X1 = 8
Xn = 30
d = 2
Using the formula of nth term for arithmetic sequence
Xn = X1 + (n-1)d
Substituting the values
30 = 8 + (n-1)2
30-8 = (n-1)2
22 = 2n -2
22+2 = 2n
2n = 24
n = 24/2
n = 12
So, it means on the 12th day he will have to do 30 pushups if he starts from 8 and increase 2 pushups each day.
Answer:
The extraneous solution is 4.
Step-by-step explanation:
First, let us calculate the value of 'x' without squaring both side of the expression. This is illustrated below:
-5 = 3x - 7
Collect like terms
-5 + 7 = 3x
2 = 3x
Divide both side by 3
x = 2/3.
Now, let us calculate the value of 'x' by squaring both side of the expression. This is illustrated below:
(-5)^2 = (3x - 7)^2
25 = (3x - 7)(3x - 7)
25 = 9x^2 - 21x - 21x + 49
9x^2 - 42x + 49 - 25 = 0
9x^2 - 42x + 24 = 0
Solving by factorisation:
Multiply the first term i.e 9x^2 and 3rd term i.e 24 together. The result is 216x^2.
Next, we shall obtain two factors of 216x^2 such that when we add them together, it will give the 2nd term i.e -42x in the equation. These factors are: -6x and -36x
Now we can write the above equation as:
9x^2 - 42x + 24 = 0
9x^2 - 6x - 36x + 24 = 0
3x(3x - 2) - 12(3x - 2) = 0
(3x - 12)(3x - 2) = 0
3x - 12 = 0 or 3x - 2 = 0
3x = 12 or 3x = 2
x = 12/3 or x = 2/3
x = 4 or 2/3.
We can see that when we solve the question without squaring both side, the value of x is 2/3. But when we solve by squaring both side, the value of x are 4 and 2/3.
Therefore, the extraneous solution to the question is 4.