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2 years ago

Can someone -that knows how to calculate how many gallons of paint will cover a room- help me??

Mathematics

1 answer:

never [62]2 years ago

5 0

Answer:

try option D that should be correct

Step-by-step explanation:

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Which of the following is a monomial?<br> ОА. 20х9 – 7х<br> Ов. 9/x<br> Ос. 11х2<br> OD. 20x – 14

777dan777 [17]

Answer:

C. 11x^2 is a monomial

Step-by-step explanation:

11x^2 is a monomial because it contains one term.

7 0

3 years ago

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Can you guys help again

dangina [55]

Answer:

Step-by-step explanation:

1 = 27

2 = 36

2 = 1,000

3 0

2 years ago

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Lena's engagement ring has a radius of 9 millimeters. What is the ring's circumference? Use 3.14 for

scoray [572]

Answer:

Given - Radius of ring is 9 millimeters

To find - Circumference

Solution -

9 millimeters = 0.9 centimeters

Circumference of circle = 2 × pie × r

= 2 × 3.14 × 0.9

= 6.28 × 0.9

= 5.652

4 0

3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago

PLEASE HELP

valina [46]

Answer:

each side of the patio measures ft.

5 0

2 years ago

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