Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
The answer to this problem “12 = 15(z-1/5) is : Z = 1
2 1/6 divided by 7/10
13/6 / 7/10 =
13/6 * 10/7 =
130/42 =
3 4/42. or 3 2/21 hours... three and two twenty-firsts
<span> (4.08)(0.7) = 2.856
--------------------------------</span>
To get the volume of the pile it is 4 x 4 x 16 so if each cord is =to 1 then the answer is 256
