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steposvetlana [31]
2 years ago
14

Bailey writes the expression g2 14g 40 to represent the area of a planned school garden in square feet. what factors can be used

to find the dimensions of her garden? (g−4)(g−10) (g 4)(g 10) (g 4)(g−10) (g−4)(g 10)
Mathematics
1 answer:
gulaghasi [49]2 years ago
5 0

The area of the planned school garden have dimensions of g + 4 and g + 10 respectively.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the area of the planned school garden as:

A = g² + 14g + 40

A = g² + 10g + 4g + 40 = g(g + 10) + 4(g + 10)

A = (g + 4)(g + 10)

The area of the planned school garden have dimensions of g + 4 and g + 10 respectively.

Find out more on equation at: brainly.com/question/2972832

#SPJ4

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Two cities are building bicycle paths. Charles City has built 5km of bicycle paths by the end of the first month, and the total
sergey [27]

Answer:

Month 4

Step-by-step explanation:

To solve this problem we must propose an equation that models the number of kilometers of bicycle trails made monthly in Charles City and in Tinsel Town

<em>For Charles City </em>we know that the number of kilometers built in the first month is 5, and it doubles every month. Then we have an exponential equation, in base 2, whose initial value is 5.

This equation has the following form:

y = C_1 (2^{x-1})

Where:

C_1 is the number of kilometers built in month 1

x is the number of months: {1, 2, 3, 4, 5 ... x}

x = 1 represents month 1.

So:

Charles\ City\ (km) = 5(2^{x-1})

<em>For Tinsel Town</em> we know that the number of kilometers built in the first month is 21 and increases at a fixed rate of 5 kilometers per month. This can be modeled by a linear equation.

Tinsel\ Town\ (km) = 21 + 5(x-1)

Where x is the number of months. x: {1, 2, 3, 4, 5 ...}

We want to know at the end of what month the total length of the cycle lanes in Charles City first exceeds the length in Tinsel Town

Then we equal both equations and clear x.

5 (2^{x-1}) = 21 + 5(x-1)\\\\5 (2^{x-1}) - (21 + 5(x-1)) = 0

Clearing x from this equation is very difficult, so to find x, we iterate until we get the value of x that causes the equation to approach 0.

For x = 3

5(2^{3-1}) - (21 +5(3-1)) = 0\\\\20- 31= -11

For x = 4

5(2^{4-1}) - (21 +5(4-1)) = 0\\\\40 - 36 = 4

<em>The value must be between x = 3 and x = 4</em>

For x = 3.8

5 (2^{3.8-1}) - (21 +5(3.8-1)) = 0\\\\34.82 - 35 = 0.18

Then x ≈ 3.8 months.

Finally we have that By the end of the fourth month the total length of the cycle lanes in Charles City exceeds the length in Tinsel Town

6 0
3 years ago
Need help people please help me
Ugo [173]

This is the answer .

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Answer: 7bb +19 ll ≥210

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

The product of the number of hours he works babysitting (bb) and the amount he earns per hour (7); plus The product of the number of hours he works lifeguarding (ll) and the amount he earns per hour 19; must be higher or equal to the amount he must earn this week (210)

Mathematically speaking:

7 bb + 19 ll ≥210

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