Answer:
y = 4 or y = 6
Step-by-step explanation:
2log4y - log4 (5y - 12) = 1/2
2log_4(y) - log_4(5y-12) = log_4(2) apply law of logarithms
log_4(y^2) + log_4(1/(5y-12)) = log_4(/2) apply law of logarithms
log_4(y^2/(5y-12)) = log_4(2) remove logarithm
y^2/(5y-12) = 2 cross multiply
y^2 = 10y-24 rearrange and factor
y^2 - 10y + 24 = 0
(y-4)(y-6) = 0
y= 4 or y=6
y = x^2 -4x
x = -1
y = (-1)^2 - 4×-1=1+4 = 5
x= 0
y = (0)^2 - 4×0 = 0
x = 1
y = 1^2 -4×1 = 1-4 = -3
x = 2
y = 2^2 -4×2 = 4-8 = -4
x=3
y = 3^2 - 4×3 = 9-12 = -3
x = 4
y = 4^2 - 4×4 = 16 - 16 = 0
now 2nd equation
y = 2x^2 + x
x = -2
y = 2 (-2)^2 + (-2)= 8-2 = 6
x = -1
y = 2 (-1)^2+(-1)= 2-1 = 1
x = 0
y = 2(0)^2 +0 = 0
x = 1
y = 2 (1)^2 + 1 = 3
x = 2
y = 2(2)^2+2= 8 + 2 = 10
Answer:
<em>MQ = 16 units</em>
Step-by-step explanation:
= 
x = 
= 2
<em>MQ</em> = 14 + 2 = <em>16 units</em>
Answer:
one solution the solution being ×=7/2
Step-by-step explanation:
one solution
