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vladimir2022 [97]
2 years ago
13

FIND RQ! Show work :)

Mathematics
1 answer:
ahrayia [7]2 years ago
5 0
Here is the answer
RQ= 52/2
RQ=26
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26) Chelsea put $7500 into an account paying 5% compounded continuously. She now has
topjm [15]

should be roughly 8 cycles. you cnat tell exactly bc we font have how often the interest is applied

4 0
2 years ago
A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Mandarinka [93]

Answer:

(a) Null Hypothesis, H_0 : \mu = 22 ounces  

    Alternate Hypothesis, H_A : \mu\neq 22 ounces

(b) The value of the test statistic is -2.687.

(c) The critical values are -1.96 and 1.96.

(d) We conclude that Reject H_0 since the value of the test statistic is less than the negative critical value.

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.

He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

<em>Let </em>\mu<em> = average ounces of passion fruit juice used to fill each bottle.</em>

(a) So, Null Hypothesis, H_0 : \mu = 22 ounces     {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}

Alternate Hypothesis, H_A : \mu\neq 22 ounces     {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounce

            n = sample of bottles = 65

So, <u><em>test statistics</em></u>  =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }  

                               =  -2.687

(b) The value of z test statistics is -2.687.

(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that Reject H_0 since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.

6 0
3 years ago
Gabriele's Pie Shop sold 80 pies last month: 7/10 were apple pies and 1/10 were peach pies. How many pies were neither apple nor
AleksAgata [21]

Answer:

16 pies were neither apple nor peach.

Step-by-step explanation:

8/10, or 4/5 of the 80 apple pies were either apple or peach, which 4/5 of 80 is 64. The remaining pies will be neither apple nor peach. 80 - 64 = 16.

7 0
2 years ago
Please help on this one!! I need it in ASAP :(
lisov135 [29]

Answer:

Hey there! here's your answer

Step-by-step explanation:

Speed = distance/Time

Speed = 3/5 ÷ 1/2

Speed = 3/5 * 2

Speed = 6/5 mph or 1.2 mph.

5 0
2 years ago
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Last winter, Anne was charged $838.35 for 9,315 KWh of electricity. What did her company charge per killowatt hour of electricit
DaniilM [7]
To solve this do:

838.35/9315= 0.09.

This means the company charged $.09 for every kilowatt of electricity used.
6 0
3 years ago
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