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2 years ago

How many feet aré in 280 yards

Mathematics

2 answers:

Katarina [22]2 years ago

7 0

840 is the answer and is equal to 280 yards

mars1129 [50]2 years ago

6 0

280 yards are equal to 840 feet

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A carpenter charges a one-time fee of $50 plus $35 for each hour on the job. If n is the number of hours on the job and c is the

Mamont248 [21]

I think it's A because 35n is independent from the 50.

3 0

3 years ago

Please help due tomorrow

mel-nik [20]

Answer: x= 2.5, y = 10

Step-by-step explanation:

<u><em>I'm going to assume that these photocopies are proportional in relations to each other.</em></u>

If they're proportional, you can set up two proportions:

$1) \frac{x}{5} =\frac{3}{6} \\\\2) \frac{5}{y} =\frac{3}{6}$

And cross-multiply:

$1) 6x = 5*3 \\\\2) 3y = 5*6$

Then solved for x and y:

$1) 6x = 15\\x=\frac{15}{6} =\frac{5}{2} =2.5 \\\\2) 3y = 30\\y=\frac{30}{3} =10$

5 0

3 years ago

Help i need help with this problem

Cloud [144]

Answer:

<em>Natalie's total spread = 18</em>

Step-by-step explanation:

The 'spread' of a crossword puzzle tournament player is computed as his/her total score minus the opponent's total score.

Natalie's scores are:

N=410+380+395+370+320+360=2,235

Opponent's scores are:

O=395+360+412+355+340+355=2,217

Natalie's total spread = 2,235 - 2,217 = +18

Natalie's total spread = 18

4 0

3 years ago

If y varies directly with x, find the value of x when y is 180 and k is 15.

BabaBlast [244]

A

Divide 180 over 15

6 0

3 years ago

Read 2 more answers

Rachel recorded the number of calls she made at work during the week:

Dmitry [639]

The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.

<h3>What is the chi-squared test statistic?</h3>

Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.

The formula for the chi-squared test statistic is;

$\sum \frac{(O_i-E_i)^2}{E_i } \\\\$

Where,

$\rm O_i$ is the observed value

$\rm E_i$ is the expected value

The chi-square test statics is;

$\rm( \frac{18-18}{18} )^2 +( \frac{14-18}{18} )^2 + (\frac{24-18}{18} )^2+( \frac{16-18}{18} )^2 \\\\ 0+ \frac{16}{18}+ \frac{36}{18} +\frac{4}{18}\\\\ \frac{56}{18} \\\\ 3.11$

Hence, the chi-squared test statistic will be 3.11.

To learn more about the chi-squared test statistic refer;

brainly.com/question/14082240

#SPJ1

5 0

2 years ago