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3 years ago

Solve the System of Equations

Mathematics

1 answer:

Softa [21]3 years ago

3 0

<u>Answer: </u>

The ordered pair value of (x, y) is (6,-11)

<u>Solution: </u>

Given Equations are

Let 8x + 15y = -117 be Equation 1 and 4x + 9y=-75 be Equation 2.

Solving Equations 1 and 2 to get the value of x and y.

Multiply Equation 2 with 4.

16x + 36y = -300

On dividing the above expression by 2, we get

8x + 18y = -150 (Change the sign to get the value of y).

-8x - 18y = 150 --- eqn 3

Now solving eqn 1 and eqn 3

8x + 15y = -117

-8x - 18y = 150

By cancelling 8x and -8x in eqn 1 and eqn 3

-3y = 33

y = -11

Substitute the value y in Equation 2.

4x + 9 (-11) = -75

4x – 99 = - 75

4x= -75 +99

4x = 24

x=6

Hence the value of x and y is (6,-11).

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Pleeease answer! Tysm!

yulyashka [42]

Answer:

The answer is 9 1/15 aka answer A.

Step-by-step explanation:

Too lazy to explain. :p

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3 years ago

Comment all that apply

choli [55]

90°
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4 0

3 years ago

Why is it that -log(x+8)=4-log(x-7) has no solution? (they are log base 2)

Lerok [7]

$-log(x+8)=4-log(x-7)$

$-\log _{10}\left(x+8\right)+\log _{10}\left(x+8\right)=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right)$

$0=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right)$

$0+\log _{10}\left(x-7\right)=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right)+\log _{10}\left(x-7\right)$

$\log _{10}\left(x-7\right)=\log _{10}\left(x+8\right)+4$

$\log _{10}\left(x-7\right)=\log _{10}\left(x+8\right)+\log _{10}\left(10000\right)$

$x-7=\left(x+8\right)\cdot \:10000$

$\mathrm{Solve\:}\:x-7=\left(x+8\right)10000:\quad x=-\dfrac{26669}{3333}$

$\mathrm{Verifying\:Solutions}:\quad x=-\dfrac{26669}{3333}\space\mathrm{False}$

$\mathrm{No\:Solution\:for\:x\in \mathbb{R}}$

3 0

3 years ago

Read 2 more answers

What is the answer to any of these

seraphim [82]

Answer:

1.The chosen topic is not meant for use with this type of problem. Try the examples below.

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7 0

2 years ago

Find a polynomial P(x) with the zeros x=2, −(2), √3, −√3

Zigmanuir [339]

Answer:

P(x) = $x^{4}$ - 7x² + 12

Step-by-step explanation:

Given zeros x = 2, x = - 2, x = $\sqrt{3}$ , x = - $\sqrt{3}$

Then the factors are (x - 2), (x + 2), (x - $\sqrt{3}$ ), (x + $\sqrt{3}$ )

and the polynomial is the product of the factors, that is

P(x) = (x - 2)(x + 2)(x - $\sqrt{3}$ )(x + $\sqrt{3}$ ) ← expand in pairs using FOIL

= (x² - 4)(x² - 3) ← distribute

= $x^{4}$ - 3x² - 4x² + 12 ← collect like terms

= $x^{4}$ - 7x² + 12

6 0

3 years ago