Answer:
Molar solubility of AgBr = 51.33 × 10⁻¹³
Explanation:
Given:
Amount of NaBr = 0.150 M
Ksp (AgBr) = 7.7 × 10⁻¹³
Find:
Molar solubility of AgBr
Computation:
Molar solubility of AgBr = Ksp (AgBr) / Amount of NaBr
Molar solubility of AgBr = 7.7 × 10⁻¹³ / 0.150
Molar solubility of AgBr = 51.33 × 10⁻¹³
Br
Se
As
Ge
Ga
Rb
Elements in the top right corner of the periodic table have the highest electronegativity. Elements on the right side have a higher electronegativity than those on the left, same with the ones on the top in comparison to those on the bottom.
2,8,1
It's in group 1, so its outershell only has 1 electron, and the other shells are completely filled, so 2 then 8. :)
Answer:
Explanation:
We can use oxidation numbers to decide which substance is reduced.
The oxidation number of Na changes from 0 in Na to +1 in Na⁺.
The oxidation number of H changes from +1 in H₂O to 0 in H₂.
1 and 4 are wrong because H₂ and Na⁺ are products.
2. is wrong because there is no H⁺ to be oxidized or reduced.
Reactants are what you put into a reaction (the things that react)
Products are the things that come out of a reaction (the things that are produced)
