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sukhopar [10]
3 years ago
14

If 7.83 g of H 2 is reacted with 15.7 g of O 2 in the reaction 2H2 + O2 → 2H2O , what is the limiting reagent?

Chemistry
1 answer:
Marrrta [24]3 years ago
8 0
When you take 7.83 g of H2, you convert to moles by dividing by the molar mass (2.02) and multiply by the number of H2s over H2Os. Then do the same for the O2. the limiting reagent in this case is the Oxygen by what I calculated.
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PLEASE HELP WILL AMRK BRAINLIEST<br> what is the atomic mass of Na3PO4?
Ira Lisetskai [31]

Answer:

163.94

Explanation:

Na = 22.99 (3)

P = 30.97

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22.99(3) + 30.97 +16.00(4) = 163.94

Hope that helps

4 0
2 years ago
Read 2 more answers
when fully inflated a hot air balloon has a volume of 1.6 *10^5 L ( liter) an average temperature of 373k and 0 967 atm . 1) Ass
Sidana [21]
1.  First, you have to find the number of moles 1.6z10^5L of gas is at 373K and 0.967atm using PV=nRT solving for n. (n=PV/RT).  Everything is in the correct units and we know R is going to be 0.08206atmL/molK since it is a constant.  
n=(0.967atmx160000L)/(0.08206atmL/molKx373K)
n=5054.8mol gas
Then you have to find the the number grams which can be found using the molar mass given as 29g/mol.  multiply 29g/mol by the number of moles of gas we found in the previous step.
5054.8molx29g/mol=146589.9g of gas
Lastly, to find the density of the gas you need to divide the mass of the gas by its volume.
146589.9g/160000L=0.916g/L

2. The dinsity of the gas at STP should be higher than the density of gas with the given conditions.  This is due to the fact that the given conditions involves a higher temperature than that of at STP which will cause the gas to expand therefore increasing the volume with out increasing the mass.  The reason why the pressure is not building up even though the pressure is higher is that the balloon is not sealed meaning the gas can maintain about atmospheric pressure while expanding since the excess are just leaves the balloon.
the answer to part 2 can be proven by the fallowing:
To find the density of the gas at STP you first multiply the molar volume of gas at STP by the number of moles of gas from part 1 to get the volume of the gas at STP.
5054.8molx22.4L/mol=113228L
Then you divide the mass form part by the new volume to get the new density.
<span>146589.9g/113228L=1.30g/L</span>

I hope this helps.  Let me know in the comments if any of it is unclear. 
4 0
3 years ago
Read 2 more answers
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LenKa [72]
I can not answer the question without the answer choices, when it is put up i will be able to answer the question. 
6 0
3 years ago
Read 2 more answers
Based on the equation 3 Cu (s) + 8 HNO3 (aq) 3 Cu(NO3)2 (aq) + 2NO (g) + 4H2O (g) how many grams of Cu would be needed to react
eimsori [14]

Answer:

Mass = 381.28 g

Explanation:

Given data:

Number of moles of HNO₃ = 16 mol

Mass of Cu needed to react with 16 mol of HNO₃ = ?

Solution:

Chemical equation:

3Cu + 8HNO₃    →     3Cu(NO₃)₂ + 4H₂O + 2NO

Now we will compare the moles of Cu with HNO₃ from balance chemical equation.

                     HNO₃         :          Cu

                        8              :         3

                       16             :       3/8×16 = 6

Mass of Cu needed:

Mass = number of moles × molar mass

Mass = 6 mol × 63.546 g/mol

Mass = 381.28 g

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Bumek [7]

Answer:

Option A.

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6 0
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