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2 years ago

What will be the new function g(x) if f(x)=2x is translated 2 units down and 3 units left?

Mathematics

1 answer:

Fed [463]2 years ago

6 0

2 units down means y is decreased by 2

3 units left mean x is decreased by 3

for

f(x)=2x

The translation is

f(x)=2(x+3)-2

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Solve c= 5/9(F-32) for F

guajiro [1.7K]

Answer:

F=9/5c+32

Step-by-step explanation:

c=5/9f-160/9

9c=5f-160

-5f=-160-9c

f=32+9/5c

f=9/5c+32

8 0

2 years ago

Ruby wanted to get an iPod for 350$ she already had 52$ saved and if she worked for 8 hours a week for 9$ an hour how many weeks

WARRIOR [948]

Answer:

I believe that the answer is 4.13 weeks

Step-by-step explanation:

Since she already has $52 you can automatically start by doing:

$350 - $52 = $298

Since she works 8 hours a week and earns $9 per hour:

8 hours x $9 = $72

Then, take $298 ÷ $72 = 4.13 or about 4 weeks

I divide 298 by 72 because $72 is how much she will earn per week, and by dividing this number by the total amount that she has left to pay narrows it down to about how long she has to save for.

Hope this helps!!

4 0

3 years ago

A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2, drawn from the 11, will

svet-max [94.6K]

The required probability is $\frac{36}{55}$

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, $\text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}$

Probability for first draw to be non-defective $=\frac{11-2}{11}=\frac{9}{11}$

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective $=\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}$

(printers after first slot = 10; total defective printers = 2)

Then, total probability $=\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}$

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

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