Which is the equation of a circle that has a center of (-1, 3) and passes through the point (3, 6)?
2 answers:
Step-by-step explanation:
The general equation of a circle with center (h,k) and radius r passing through a point (x,y) is given by

Here, r²= {3-(-1)}²+(6-3)²
=( 3+1)²+(3)²
= 16+9
= 25
So, the equation;
{x-(-1)}²+(y-3)²= 25
or,(x+1)²+(y-3)²=25
or, x²+2x+1+y²-6y+9-25=0
or,x²+y²+2x-6y-15=0
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Step-by-step explanation:
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