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Ainat [17]
3 years ago
13

Which is the equation of a circle that has a center of (-1, 3) and passes through the point (3, 6)?

Mathematics
2 answers:
Mars2501 [29]3 years ago
7 0

Step-by-step explanation:

The general equation of a circle with center (h,k) and radius r passing through a point (x,y) is given by

{(x - h)}^{2}  +   {(y - k)}^{2}  =  {r}^{2}

Here, r²= {3-(-1)}²+(6-3)²

=( 3+1)²+(3)²

= 16+9

= 25

So, the equation;

{x-(-1)}²+(y-3)²= 25

or,(x+1)²+(y-3)²=25

or, x²+2x+1+y²-6y+9-25=0

or,x²+y²+2x-6y-15=0

Anna [14]3 years ago
4 0

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