Which is the equation of a circle that has a center of (-1, 3) and passes through the point (3, 6)?
2 answers:
Step-by-step explanation:
The general equation of a circle with center (h,k) and radius r passing through a point (x,y) is given by

Here, r²= {3-(-1)}²+(6-3)²
=( 3+1)²+(3)²
= 16+9
= 25
So, the equation;
{x-(-1)}²+(y-3)²= 25
or,(x+1)²+(y-3)²=25
or, x²+2x+1+y²-6y+9-25=0
or,x²+y²+2x-6y-15=0
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Answer:
x=3, y= - 2
Step-by-step explanation:
4x + 3y = 6
x-3y= 9
x=9+3y
4.(9+3y)+3y=6
36+12y+3y=6
15y = - 30
y = - 2
=> x= 9+3y
x= 9+ 3.(- 2)
x= 3
Answer:
8 + 7i
Step-by-step explanation:
Change the sign of the imaginary part.
The conjugate of 8 - 7i is 8 + 7i.