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zalisa [80]
3 years ago
15

A fence was build arpund a square yard. It took 500 feet² of lumber to build the fence. The fence is five feet tall. What is the

area of the yard inside the fence?
Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

  625 square feet

Step-by-step explanation:

The length of the fence is its area divided by its height:

  A = LW

  500 ft² = L(5 ft)

  (500 ft²)/(5 ft) = 100 ft = L

This encloses a square, so the side of the square is 1/4 of this length:

  side = (100 ft)/4 = 25 ft

The yard's area is the square of the length of its side dimension:

  yard area = (25 ft)² = 625 ft²

The area of the yard inside the fence is 625 square feet.

_____

<em>Comment on units</em>

If you keep units with numbers, you know that dividing 500 ft² by 5 ft will give a measure of 100 ft. This is a linear measure, not an area measure, so tells you that this is <em>not the answer</em> to the question of yard area.

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What needs to be corrected in this construction of a line parallel to line AB passing through C?
UNO [17]

The option that needs to be corrected in this construction of a line parallel to line AB passing through C is C: the second arc should be centered at C.

<h3>Why should the second arc be centered at C?</h3>

The second arc should be centered at C because as it crosses passing through Line C, it is seen that it was not touching or intersecting AB and so one can say that it is parallel to it.

Looking at the other lines, we will see that they are all touching AB and are not running parallel to it.

Hence, The option that needs to be corrected in this construction of a line parallel to line AB passing through C is C: the second arc should be centered at C.

Learn more about line parallel;

brainly.com/question/1439525

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5 0
3 years ago
A city currently has 31,000 residents and is adding new residents steadily at the rate of 1200 per year. If the proportion of re
dlinn [17]

Answer:

Population of the city after 7 years from now, P(7) = 6370

Given:

Initial Population, P_{i} = 31000

rate, r(t) = 1200 /yr

S(t) = [/tex]\frac{1}{1 + t}[/tex]

Step-by-step explanation:

Let the initial population be  P_{i} = 31000

The population after T years is given by the equation:

P(T) = P_{i}S(T) + \int_{0}^{T}S(T - t)r(t) dt          (1)

Thus, the population after 7 years from now is given by using eqn (1):

P(7) = \frac{3100}{1 + 7} + 1200\int_{0}^{7}\frac{1}{8 - t} dt

P(7) = 3875 - 1200ln(8 - t)|_{0}^{7}

P(7) = 3875 - 1200ln(8 - t)|_{0}^{7}

P(7) = 3875 - 1200(ln(1) - ln(8))

P(7) = 3875 + 2495 = 6370

6 0
3 years ago
A school has a 20:2 student - teacher ratio graph a line representing this scenario part b what is the unit rate
9966 [12]
The unit rate is 10:1 because unit rates are out of 1
You would find that by dividing 20 and 2 by the same number to get to one for this specific problem. 20 divided by two is ten and two divided by two is one. So that is your answer for part b. I can’t draw a graph however so sorry
5 0
3 years ago
The Greens are moving. Their real estate agent located 81 houses listed for sale in their price range. Of those houses listed fo
poizon [28]

Answer:

We know that:

There is a total of 81 houses:

51 had a finished basement.

56 had a three-car garage.

37 had a finished basement and a three-car garage.

a)  How many had a finished basement but not a three-car garage?

51 had a finished basement, and 37 have a finished basement and the garage, then:

51 - 37 = 14 hoses have only the basement.

b) How many had a three-car garage but not a finished basement?

Same reasoning as above:

56 - 37 = 19 houses only have the garage.

c) How many had either a finished basement or a three-car garage?

Now we only count the ones that have one finished thing, in this case, we already found the number of houses that have only the garage or only the basement, then the number of houses that either had a finished basement or a finished garage is:

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7 0
4 years ago
A pretzel company calculated that there is a mean of 75.4 broken pretzels in each production run with a standard deviation of 5.
Snowcat [4.5K]

Answer:

P [ Z < 66 ]  = 35,15 %

Step-by-step explanation:

Normal Distribution

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Standard deviation  σ = 5,2

Then:

P [ Z < 66 ]  =  ( 66 - 75,4 ) / 5,2

P [ Z < 66 ]  = - 9,4 / 5,2

P [ Z < 66 ]  = - 1,81

In z-table we look for the reciprocate area for that  z score and find

P [ Z < 66 ]  = 0,3515

P [ Z < 66 ]  = 35,15 %

6 0
3 years ago
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