Answer:
- one orange costs $0.35 and one grapefruit costs $0.45
Step-by-step explanation:
<em>let grapefruits be g , let oranges be o</em>
so first equation:
→2g + 3o = $1.95
→g = ($1.95 - 3o)/2
so second equation:
→ 3g + 2o = $2.05
→ g = ($2.05 - 2o)/3
Solving simultaneously:
→ ($2.05 - 2o)/3 = ($1.95 - 3o)/2
→ 2($2.05 - 2o) = 3($1.95 - 3o)
→ 4.1 - 4o = 5.85 - 9o
→ - 4o + 9o = 5.85 - 4.1
→ 5o = 1.75
→ o = $0.35
Therefore one orange costs $0.35
Then one grapefruit costs g → ($1.95 - 3o)/2
→ g = ($1.95 - 3(0.35))/2
→ g = 0.45
Therefore one grapefruit costs $0.45
The answer to the question is a

- Given - <u>a </u><u>cone</u><u> </u><u>with </u><u>volume</u><u> </u><u>7</u><u>6</u><u>9</u><u>?</u><u>3</u><u> </u><u>ft³</u><u> </u><u>,</u><u> </u><u>having </u><u>a </u><u>height </u><u>of </u><u>1</u><u>5</u><u> </u><u>ft</u>
- To calculate - <u>radius </u><u>of </u><u>the </u><u>cone</u>
We know that ,

<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula</u><u> </u><u>stated </u><u>above </u><u>,</u>

therefore ,
<u>radius </u><u>=</u><u> </u><u>7</u><u> </u><u>cm</u>
hope helpful ~
1230 1203 1302 1320 1032 1023 2130 2103 2301 2310 2032 2023 3210 etc