A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
Answer:
The first one is not liner
Step-by-step explanation:
This isn't linear because the y values increase inequally. It adds 2 and then 3 instead of keeping a constant rate
Answer:-12-9x-4584671418
Step-by-step explanation:
4×17-x=84
68-x=84
-x=16
x=-16
To solve this problem you must apply the proccedure shown below:
1. You have:
<span>
In(2x+3)=7
2. Then, you must apply log(e), as below:
</span><span>
In(2x+3)=ln(e^7)
3. Now, you obtain:
2x+3=e^7
4. Youy must clear the variable "x", as below:
2x=e^7-3
</span> x=(e^7-3)/2
<span>
5. Therefore, the value of "x" is:
x=546.817
</span><span>
The answer is: </span>x=546.817<span> </span>