3 years ago

Which fraction is less than 1/2? Is it A:3/8 B:5/8 C:5/7 or D:9/16

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

The answer is A because it is less than 1-2

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Two angles are supplementary. One is 56° more than three times three times the other. Find the measures of the angles.

kaheart [24]

Supplementary means they equal 180 when added. Therefore:

X+56+3x=180
Combine common units
4x+56=180
Subtract 56 from both sides
4x=124
Divide by 4
X=31

Now we know the smaller angle is 31 degrees. Now we plug that into the larger angle:
3(31)+56
93+56
149

The larger angle is 149 degrees.

I hope this Helps!

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3 years ago

The graph shows the time and distance Mr. Patel has driven while on a business trip. What is the unit rate in miles per hour he

boyakko [2]

Answer:75. y/x = 75/1 = 75

Step-by-step explanation:

y/x = 75/1 = 75

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3 years ago

Write an equation of the perpendicular bisector of the segment with end points M(1,5) and N(7,-1)

vitfil [10]

The perpendicular bisector of the segment passes through the midpoint of this segment. Thus, we will initially find the midpoint P:

$P=\dfrac{(1,5)+(7,-1)}{2}=\dfrac{(8,4)}{2}=(4,2)$

Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:

$m_r=\dfrac{\Delta y}{\Delta x}=\dfrac{5-(-1)}{1-7}=\dfrac{6}{-6}\iff m_r=-1$

$p\perp r\Longrightarrow m_p\cdot m_r=-1\Longrightarrow m_p\cdot(-1)=-1\iff m_p=1$

We can calculate the equation of p by using its slope and its point P:

$y-y_P=m_p(x-x_P)\\\\
y-2=1\cdot(x-4)\\\\
y-2=x-4\\\\
\boxed{p:~~y=x-2}$

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3 years ago

There are 475 students and teachers going on a field trip a school bus holds 78 people how many buses are needed for the trip

kap26 [50]

7 is the answer, you have to divide 475 by 78 and you get 6.08974358974359 but you round it up to 7 to make sure you have enough buses

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3 years ago

Evaluate (if possible) the six trigonometric functions of the real number. (If not possible, enter IMPOSSIBLE.)

kotegsom [21]

$\sin(t) = \frac{1}{2} 
\\
\\ \cos(t) = - \frac{ \sqrt{3} }{2} 
\\
\\ \tan(t) = \frac{\sin(t)}{\cos(t)}= - \frac{1}{ \sqrt{3} } 
\\
\\ \csc(t) = \frac{1}{\sin(t)}= 2 
\\
\\ \sec(t) =\frac{1}{\cos(t)}=- \frac{2}{ \sqrt{3}} 
\\
\\ \cot(t) = \frac{1}{\tan(t)}=- \sqrt{3}$

3 0

3 years ago