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2 years ago

11

Erin has four shirts (whites, blue, red, black) and two pairs of pants (black, blue). She randomly chooses a shirt and a pair of

pants. what is the probability that they are the same color?

1 answer:

Dennis_Churaev [7]2 years ago

3 0

Answer:

25%

Step-by-step explanation:

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Find the unknown word for the sum of the blank 8 + blank is 10

alina1380 [7]

8 + _ = 10
10 - 8 = 2
8 + 2 = 10

6 0

3 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

3 years ago

I'LL give brainliest!!

Brums [2.3K]

Answer: B

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Can someone help me!!!!!!

andriy [413]

Answer:

The value of x is 4, 3rd point.

Step-by-step explanation:

Move all the variables to one side & move unknown value to the other side :

4x - 3 = 2x + 5

4x - 2x = 5 + 3

2x = 8

Then solve it :

2x = 8

x = 8/2

x= 4

5 0

4 years ago

Read 2 more answers

In quadrilateral ABCD, BN and DM are drawn perpendicular to AC such that BN = DM. Prove that O is the midpoint of BD

GaryK [48]

Answer:

Step-by-step explanation:

Given :

In the given quadrilateral ABCD,

BN and DM are the perpendiculars drawn to AC such that,

BN = DM

To prove:

Point O is the midpoint of segment BD.

Or

OD = OB

Solution:

In ΔOMD and ΔONB,

∠MOD ≅ NOB [Vertical angles]

∠M ≅ ∠N ≅ 90° [Given]

Therefore, by AA property of similarity,

ΔOMD ~ Δ ONB

Therefore, their corresponding sides will be proportional,

$\frac{DM}{BN}=\frac{OD}{OB}$

Since BN = DM,

OD = OB

Hence O is the midpoint of BD.

4 0

4 years ago