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kodGreya [7K]
3 years ago
14

[15 POINTS] Please help me!

Mathematics
2 answers:
steposvetlana [31]3 years ago
8 0

Answer:

1) y=2x+7      2) y=4 and y=3

Step-by-step explanation:

1) you start knowing that the slope-intercept equation is y=mx+b. M stands for your slope so you just plug 2 in for m. Then you plug in the x to see how to make it equal 1. As you look at it you realize that 2*-3 is -6 and you need to add 7 to get to one. Therefore the seven would be the B.

2) Since there is no slope the lines just go on the horizon at the y point of 4 or 3.

kari74 [83]3 years ago
5 0
Hello i don't know the answer
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If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
MaRussiya [10]

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the figure could be a rhombus because the 2 lines of symmetry bisect the angles

Step-by-step explanation:

7 0
3 years ago
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The distance from the tip of a slice of pizza to the crust is 7 inches.
Mice21 [21]

Answer:

radius

Step-by-step explanation:

4 0
2 years ago
Please help anybody I need to fast please
elena55 [62]
Answer:
D. t = -1

step-by-step explanation:
that side should be 180 degrees and the whole is 360 but we are only measuring half
so (20t + 5) = 15t
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4 0
2 years ago
What is the sum of a 7-term geometric series if the first term is -6, the last term is -24,576, and the common ratio is 4?
Zanzabum
<h3><u>Answer:</u></h3>

Hence, the sum of a 7-term geometric series is:

-32766.

<h3><u>Step-by-step explanation:</u></h3>

We have to find the sum of a 7-term geometric series (i.e. n=7) if the first term(a) is -6, the last term is -24,576, and the common ratio(r) is 4.

We know that the sum of the 7-term geometric series is given as:

S_n=a\times (\dfrac{r^n-1}{r-1})

On putting the value of a,n and r in the given formula we have:

S_7=(-6)\times (\dfrac{4^7-1}{4-1})\\\\\\S_7=-32766

Hence, the sum of a 7-term geometric series is:

-32766.

3 0
3 years ago
Read 2 more answers
Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

α = 58.1°

sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

Checking: 74+58.1+47.9 = 180° ok

c) Using Heron A² = p(p-a)(p-b)(p-c)

p = a+b+c/2

p=126+110+142.6/2

p=189.3

A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)

A = 6661.5 ft²

1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

The city will not approve

7 0
3 years ago
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