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1 year ago

Find the area of the regular polygon

Mathematics

1 answer:

Aleksandr-060686 [28]1 year ago

4 0

Answer:

a = 337.214 m2

Step-by-step explanation:

hope this helps

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The largest angle is a triangle is 110°. Of the remaining two angles, one is 4° less than the other angle. Find the

Masja [62]

Answer:

Do 180-110=70 Then have it where 70/2=35. 35+4=39, 35-4=31, so the three angles are 39, 110, and 31.

Step-by-step explanation:

7 0

3 years ago

Sue wants to know whether wearing sunglasses improves driving performance. If she uses an independent groups design, she would m

MakcuM [25]

Answer:

randomly requiring half the drivers to drive with sunglasses and the other half to drive without sunglasses.

Step-by-step explanation:

When employing an independent group design in a research or experimental study, the different groups in the study are assigned entirely different subjects such that, subjects in the treatment group are different from those in the control group. Therfore, adopting an independent group design in the scenario described above means diving the subjects into two at random with one half driving with sunglasses and the other half having to drive without it.

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2 years ago

The ratio of sues age to her fathers age is 2:7 in three years their ages will total 60, how old is sue and her dad right now

USPshnik [31]

Sue is 12 and her father is 42

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3 years ago

Read 2 more answers

Find an equation for the line that passes through the points (5.-5) and (-4,-2)

ANEK [815]

Answer:

$\large\boxed{y=-\dfrac{1}{3}x-\dfrac{10}{3}\to x+3y=-10}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (5, -5) and (-4, -2).

Substiute:

$m=\dfrac{-2-(-5)}{-4-5}=\dfrac{-2+5}{-9}=\dfrac{3}{-9}=-\dfrac{1}{3}$

Put the value of the slope and the coordinates of the point (5, -5) to the equation of a line:

$-5=-\dfrac{1}{3}(5)+b$

$-5=-\dfrac{5}{3}+b$ add 5/3 to both sides

$-\dfrac{15}{3}+\dfrac{5}{3}=b\\\\-\dfrac{10}{3}=b\to b=-\dfrac{10}{3}$

Finally we have the equation of a line in the slope-intercept form:

$y=-\dfrac{1}{3}x-\dfrac{10}{3}$

Convert to the standard form (Ax + By = C):

$y=-\dfrac{1}{3}x-\dfrac{10}{3}$ multiply both sides by 3

$3y=-x-10$ add x to both sides

$x+3y=-10$

4 0

3 years ago

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago