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joja [24]
3 years ago
7

When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year f

or the next 6 years. At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year? a) 3/10 b) 2/5 c) 1/2 d) 2/3 e) 6/5
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

Option D is the correct answer.

Step-by-step explanation:

Initial height = 4 feet

Given that the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

Let the rate of growing each year be g.

After 6 years height of tree = 4 + 6g

After 4 years height of tree = 4 + 4g

At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.

That is

                4+6g=4+4g+\frac{4+4g}{5}\\\\4+6g=\frac{20+20g+4+4g}{5}\\\\20+30g=24+24g\\\\6g=4\\\\g=\frac{2}{3}ft/year

Option D is the correct answer.    

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Step-by-step explanation:

You want the dimensions of a rectangle and square such that they have the same perimeter, but the square has an area of 36 more square feet. The rectangle is twice as long as wide.

<h3>Setup</h3>

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  9/4x² -2x² = 36 = x²/4   ⇒   x = √(36·4) = 6·2 = 12 . . . . width of rectangle

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