answer:
a. scarf costs today = $6
b. scarf costs 3 days from now = $3
step-by-step explanation:
- 1/2 off means you would multiply the amount by 1/2 then subtract
a. original price of scarf: $12
12 X 1/2 = 6
12 - 6 = 6
— scarf costs today = $6
- do the same thing but this time it is a different number
b. 12 X 3/4 = 9
12 - 9 = 3
— scarf costs 3 days from now = $3
Answer:
The temperature in the greenhouse was at least 68 degrees before the heater stopped working.
Step-by-step explanation:
It was at 68 then it dropped by 2 degrees.
Answer:
Step-by-step explanation:
a.
2y - 3x = 5
2(-2) - 3x = 5
-4 - 3x = 5
-3x = 9
x = -3
(-3,-2) is another solution
b.
(-1,1)
2y - 3x = 5
2(1) - 3(-1) = 5
2 + 3 = 5
5 = 5
true, the point is a solution to the equation because the equation is true after substituting x and y with the point (-1,1)
(4,1)
2y - 3x = 5
2(1) - 3(4) = 5
2 - 12 = 5
-10 = 5
not true, the point is not a solution to the equation because the equation is not true after substituting x and y with the point (4,1)
c. You can use the points from the given (-1,1) and (-3,-2) to form a line. You then shade whichever half solves the solution using points on the graph.
Answer:
a = 3, b = 0, c = 0, d = -2
Step-by-step explanation:
<em>To find the reflection Multiply the matrices</em>
∵ The dimension of the first matrix is 2 × 2
∵ The dimension of the second matrix is 2 × 3
<em>1. Multiply the first row of the 1st matrix by each column in the second matrix add the products of each column to get the first row in the 3rd matrix.</em>
2. Multiply the second row of the 1st matrix by each column in the second matrix add the products of each column to get the second row of the 3rd matrix
![\left[\begin{array}{ccc}1&0\\0&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%26-1%5Cend%7Barray%7D%5Cright%5D)
× ![\left[\begin{array}{ccc}0&3&0\\0&0&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%263%260%5C%5C0%260%262%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}(1*0+0*0)&(1*3+0*0)&(1*0+0*2)\\(0*0+-1*0)&(0*3+-1*0)&(0*0+-1*2)\end{array}\right]=\left[\begin{array}{ccc}0&3&0\\0&0&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%281%2A0%2B0%2A0%29%26%281%2A3%2B0%2A0%29%26%281%2A0%2B0%2A2%29%5C%5C%280%2A0%2B-1%2A0%29%26%280%2A3%2B-1%2A0%29%26%280%2A0%2B-1%2A2%29%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%263%260%5C%5C0%260%26-2%5Cend%7Barray%7D%5Cright%5D)
Compare the elements in the answer with the third matrix to find the values of a, b, c, and d
∴ a = 3
∴ b = 0
∴ c = 0
∴ d = -2
