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Annette [7]
2 years ago
5

19 there is a frog and snake exhibit at

Mathematics
1 answer:
Norma-Jean [14]2 years ago
5 0

Answer:

b.42

Step-by-step explanation:

the ratiois is 3 to 4 .So every 4 snakes is to 3 frogs so since there are 24 snakes devide the 24 by 4 which will give u 6 then multiply the answer by 3 which will give u 18 which represents the total number of frogs then add 18 +24 which is 42.

so then total number of frogs is 42.

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Which expression models the phrase “Wally mowed two more lawns than he mowed last week”?
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Answer: n+2

Two lawns more than last week so two more than something with n being that something is; n+2
4 0
4 years ago
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Marcos had 15 coins in nickels and quarters. He had 3 more quarters than nickels. He wrote a system of equations to represent th
hodyreva [135]

Answer:

There are 6 coins in nickels and 9 coins in quarters.

Step-by-step explanation:

Now, to find the solution.

According to question:

The number of nickels = x.

The number of quarters = y.

So, the total number of coins:

x+y=15.

He had 3 more quarters than nickels.

Thus,

y=x+3 .....(1)

Now, to get the solution:

x+y=15

Substituting the equation (1):

x+(x+3)=15

x+x+3=15

2x+3=15

<em>Subtracting both sides by 3 we get:</em>

<em />2x=12<em />

<em>Dividing both sides by 2 we get:</em>

x=6.

<em>The number of nickels = 6.</em>

Now, substituting the value of x in equation (1):

y=x+3\\\\y=6+3\\\\y=9.

<em>The number of quarters = 9.</em>

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6 0
3 years ago
Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation
just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation v(t)= 6t^2-18t+12. We are asked to find the distance that the particle will travel in its first 2 seconds.

s(t)=\int |v(t)|dt

s(t)=\int\limits^2_0 |6t^2-18t+12|dt

Now, we will eliminate the absolute value sign as:

s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt

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s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1

s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))

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7 0
3 years ago
Ryan has a board that is 5 feet long. how many 1/3-foot sections can he cut from this board?
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Ryan can cut 15 pieces from the board
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4 years ago
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Answer:

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Step-by-step explanation:

Given:

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3 years ago
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