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Alex73 [517]
3 years ago
13

Can U Help MeSolve This?

Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

A) 65

B) 5

C) 242

D) 531

E) 36

Step-by-step explanation:

A) Let the unknown term be x.

Difference between 5 & 9 = 4

Difference between 9 & 17 = 8 = 4×2

Difference between 17 & 33 = 16 = 8×2

It is observed that the difference between two terms is getting doubled. So,

Difference between 33 & x = 16×2 = 32

∴ x = 33 + 32 = 65

B) Let the unknown term be x.

Difference between 20 & 12 = 8

Difference between 12 & 8 = 8/2 = 4

Difference between 8 & 6 = 4/2 = 2

It is observed that the difference between two terms is getting halved.

Difference between 6 & x = 2/2 = 1

∴ x = 6 - 1 = 5

C) Let the unknown term be x.

Difference between 2 & 8 = 6

Difference between 8 & 26 = 18 = 6×3

Difference between 26 & 80 = 54 = 18×3

It is observed that the difference between two terms is getting tripled.

Difference between 80 & x = 54×3 = 162

∴ x = 80 + 162 = 242

D) Let the unknown term be x.

Difference between 36 & 69 = 33

Difference between 69 & 135 = 66 = 33×2

Difference between 135 & 267 = 132 = 66×2

It is observed that the difference between two terms is getting doubled.

Difference between 267 & x = 132×2 = 264

∴ x = 267 + 264 = 531

E) Let the unknown term be x.

4 = 2²

9 = 3²

16 = 4²

25 = 5²

It is observed that all the terms in the sequence are squares of consecutive natural numbers.

So, x = 6² = 36

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Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
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Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
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