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lawyer [7]
2 years ago
15

A jar contains only dimes and nickels. The total number of coins in the jar is

Mathematics
1 answer:
pogonyaev2 years ago
4 0

Answer:

5 dimes and 10 nickels

Step-by-step explanation:

0.1d + 0.05n = 1

d + n = 15

d + 0.5n = 10

d + n = 15

0.5n = 5

n = 10

d + n = 15

d + 10 = 15

d = 5

Answer: 5 dimes and 10 nickels

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Solution,

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i. Let n(I intersection T ) be X

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<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
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laiz [17]

Answer:

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Step-by-step explanation:

To represent the expression :

Sum of 11 and y ; greater than - 33

Sum of 11 and y ; 11 + y

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Hence ;

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