8/9 - 2/3 = 8/9 - 6/9 = 2/9 of a pound left
She had 8/9 of a pound of birdseed to begin with. She used 2/3 of a pound of birdseed into her feeders. You have to get a common denominator, would be 9 and when you subtract what she used from what she had you get 2/9 of a pound of birdseed left.
9. 6
10. 13
11. 4
12. 30
13. 6/7
14. 5/9
15. 1/3
16. 11/4
17. 7/5
18. 1/2
Hope This Can Help You
Answer:
Ahh! What a classic: Systems of Equations!
So, if you don't know what a system of equations is, its basically two equations with two variables combined into a system.
So, let x=# of pigs
And also, Let y=# of chickens
Let's make our first equation!
This is because there are 13 animals in a barn.
So then, knowing that a pig has 4 legs and a chicken 2:
This is because there are 40 legs in total, and we multiply the variable because that's how many legs each creature has.
So, here is our system!
Through Substitution (the inputting of something instead of a variable):
Then, we input it into the next equation:
This means that there are 6 chickens, and by inputting it into the first equation:
So there you have it!
FYI there are 6 chickens and 7 pigs.
Hope this helps!
P.S. Stay Safe!
Answer:
6 feet from the edge of the wall
The question is missing some parts. To complete, J is the event of getting a jack and R is getting a red card.
The first question is to look for the P (J) and P (R) =
P (J) = 4/52 = 0.077; since there are only 4 jacks in a standard deck.
P (R) = 26/52 = 0.5; 26 because there are 13 each for diamonds and hearts.
The second question is to describe the event J and R in words. Then look for that event’s probability.
The card is a red jack or the card is red and a jack. P (J and R) = 2/52 = 0/038
The last question is explain why P (J or R) is not equal to P (J) + P (R). Then use the general addition rule to compute for P (J or R).
The event card is red and card is jack are not mutually exclusive meaning two or more events can happen simultaneously. Thus one will count two cards twice unless using the general probability addition formula.
The probability for P (J ∪ R) is:P (J ∪ R) = 2 + 2 + 24 / 52 = 28/52 = 0.0538Or the other solution would be:P (J ∪ R) = 4/52 + 26/52 + 2/52 = 28/52 = 0.0538
