The ratio 11:4 means that the total number of spaces is a multiple of 15 parts, this multiple is what value is assigned to each part.
450/15=30 so each part is equal to 30 spaces
Full sized car spaces are 11*30=330 spaces
Compact car spaces are 4*30=120 spaces.
Answer:
$60
Step-by-step explanation:
Let's say we need t $2 bills and v $5 bills.
We need 9 more $2 bills than $5 bills, so:
t = 9 + v
We also know that the amount of money in t $2 bills is 2 * t = 2t. The amount of money in v + 9 $5 bills is 5 * (v + 9) = 5v + 45. These amounts are equal:
5v + 45 = 2t
Plug v + 9 in for t in 5v = 2t + 18:
5v = 2t + 18
5v = 2 * (9 + v) + 18
5v = 18 + 2v + 18
3v = 36
v = 12
We have 12 $5 bills, so that total cost is 12 * 5 = $60.
<em>~ an aesthetics lover</em>
Answer:
11*pi/36
Step-by-step explanation:
Answer:
Answer is C. VT just took the test and this was the answer 100 percent.
Step-by-step explanation:
just took the test
Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:
![\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7D-%5Cfrac%7B3%7D%7B16%7D%5CRightarrow%20%5Cfrac%7B6%7D%7B16%7D-%5Cfrac%7B3%7D%7B16%7D%3D%5Cfrac%7B3%7D%7B16%7D)
Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.
![1](https://tex.z-dn.net/?f=1%3C%5Cfrac%7B3%7D%7B16%7D%2B%28n-1%29%5Ccdot%20%5Cfrac%7B3%7D%7B16%7D)
Let us solve for n.
![1](https://tex.z-dn.net/?f=1%3C%5Cfrac%7B3%7D%7B16%7D%2B%5Cfrac%7B3%7D%7B16%7Dn-%5Cfrac%7B3%7D%7B16%7D)
![1](https://tex.z-dn.net/?f=1%3C%5Cfrac%7B3%7D%7B16%7Dn)
![1\cdot \frac{16}{3}](https://tex.z-dn.net/?f=1%5Ccdot%20%5Cfrac%7B16%7D%7B3%7D%3C%5Cfrac%7B16%7D%7B3%7D%5Ccdot%20%5Cfrac%7B3%7D%7B16%7Dn)
![5.333](https://tex.z-dn.net/?f=5.333%3Cn)
![n>5.333](https://tex.z-dn.net/?f=n%3E5.333)
We can also write next terms of our sequence as:
![\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B16%7D%2C%5Cfrac%7B6%7D%7B16%7D%2C%20%5Cfrac%7B9%7D%7B16%7D%2C%5Cfrac%7B12%7D%7B16%7D%2C%5Cfrac%7B15%7D%7B16%7D%2C%5Cfrac%7B18%7D%7B16%7D)
Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.