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RUDIKE [14]
3 years ago
12

Let B be between a and C use the segment addition postulate to solve for W

Mathematics
1 answer:
fomenos3 years ago
6 0

Answer:

Value of w = 6

Step-by-step explanation:

Given:

AB= 4w-4

BC = 2w-8

AC = 24

Find:

Value of w

Computation:

AB + BC = AC

4w - 4 + 2w - 8 = 24

6w - 12 = 24

6w = 24 + 12

6w = 36

w = 6

Value of w = 6

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Step-by-step explanation:

The answer is 0

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Suppose an airline policy states that all baggage must be box shaped with a sum of length, width, and height not exceeding 174 i
Leya [2.2K]

Answer:

The square-based box with the greatest volume under the condition that the sum of length, width, and heigth does not exceed 174 in is a cube with each edge of 58 in and a volume of 195112 in^{3}

Step-by-step explanation:

For this problem we have two constraints, that are as follows:

1) Sum of length, width, and heigth not exceeding 174 in

2) Lenght and width have the same measure (square-based box)

We know that volume is equal to the product of all three edges, and with the two conditions into account we have the next function:

V=(w^{2})(174-2w)\\V=174w^{2}-2w^{3}

The interval of interest of the objective function is [0, 87]

This problem requieres that we maximize the function that defines the volume. We start calculating the derivative of the function, wich is:

V'=348w-6w^{2} \\V'=(348-6w)(w)

We need to remember that the derivative of a function represents the slope of said function at a given point. The maximum value of the function will have a slope equal to zero.

So we find the value in wich the derivative equals zero:

0=(348-6w)(w)\\w_1=0\\w_2=348/6=58

The first value (w=0) will leave us with a 'height-only box', so the answer must be w=58 in

The value is between the interval of interest.

And, once we solve for the constraints, we have that:

Lenght = Width = Heigth = 58 in

Volume = 195112 in^{2}

8 0
3 years ago
Write the expression representing the total number of miles run: Jazmin ran 3 miles on Monday. For the next 4 days, she ran x mi
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Answer:

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Step-by-step explanation:

3 0
3 years ago
The weight of an object on mars varies directly is proportional as the weight of the object on earth a 75 pound object on earth
dedylja [7]

Answer:

It weighs 40 pounds on mars

Step-by-step explanation:

Direct proportion is the relationship between two variables when their ratio is equal to a constant value

  • It can be expressed as y = k x, where y varies directly as x and k is constant of variation
  • It can be expressed as  \frac{y_{1}}{x_{1}}=\frac{y_{2}}{x_{2}}=k

∵ The weight of an object on mars varies directly as the weight

    of the object on earth

∴ w(m) = k × w(e)

∵ The weight of the object on earth is 75 pound

∴ w(e) = 75

∵ The weight of this object on mars is 25 pounds

∴ w(m) = 25

- Substitute them in the equation of variation

∵ 25 = k × 75

- Divide both sides by 75

∴ \frac{1}{3} = k

∴ w(m) = \frac{1}{3} × w(e)

∵ An object weighs 120 pounds on earth

∴ w(e) = 120

- Substitute it in the equation of variation

∴ w(m) = \frac{1}{3} × 120

∴ w(m) = 40

∴ It weighs 40 pounds on mars

5 0
3 years ago
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