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Ede4ka [16]
3 years ago
14

What is 63.48 rounded off to 1 decimal place?

Mathematics
1 answer:
Lilit [14]3 years ago
5 0

Answer:

63.5

Step-by-step explanation:

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Hi ! if you come across this can you please help me out?:) tysm
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Answer: y=4x-2

Step-by-step explanation:

Since you are looking for y-intercept, the point has to be on the vertical line and the slope is 4 so it has to go up 4 to the right 1

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I don’t know if this is right, I’m stuck. Help!
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Answer:

C

Step-by-step explanation:

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3 years ago
- Two cars leave the same parking lot, with one heading north and the other heading east. After several minutes, the northbound
PIT_PIT [208]

Answer:

Step-by-step explanation

Use Pythagoras theorem. The distance between the cars, 8km, is the hypotenuse of a right angled triangle, one leg of which is 6km and the other of which is, say, x km

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4 0
3 years ago
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
Simplify: square root of 81+18<img src="https://tex.z-dn.net/?f=%5Csqrt%7B7%7D" id="TexFormula1" title="\sqrt{7}" alt="\sqrt{7}"
Lemur [1.5K]

\sqrt{81 \:  +  \: 18 \sqrt{7}  \:  +  \: 7}

  • Factor the indicated expression:

\sqrt{(9 \:  +  \:  \sqrt{7} ) ^{2} }

  • Simplified the index, the root and also the exponent using the number 2.

\boxed{ \bold{9 \:  +  \:  \sqrt{7} }}

<h3><em><u>MissSpanish</u></em> </h3>
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2 years ago
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