<span>The probability of getting exactly 6 heads is: 10!/6!(10-6)! * (1/2)^6 (1 - 1/2)^4 = 0.205 or 20.6 %</span>
f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0
tan2(x) + √3[tan(x)] - tan(x) - √3 = 0
Factor into
[-1 + tan(x)]*[√3 + tan(x)] = 0
which means
[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0
Then
tan(x) = 1
tan-1(1) = pi/4 radians
For the other equation
[√3 + tan(x)] = 0
tan(x) = -√3
tan-1(-√3) = -pi/3
so that
x = pi/4 or -pi/3 in the interval [0, 2pi]
Imagine to have three segment: 1 is x, another is x+7 and the last is x-5. You know that their sum is 50, so you can write:
x+(x+7)+(x-5)=50
simplify:
3x+7-5=50
3x=48
x=16
16+7=23
16-5=11
So the thee sides are 11, 16 and 23.
Hope this helped.
Answer:
103
Step-by-step explanation:
Answer:
x=3
Step-by-step explanation:
