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Alina [70]
2 years ago
5

The width of the rectangle is 75% of its length. (24 in.)

Mathematics
1 answer:
sashaice [31]2 years ago
7 0

Answer:

Step-by-step explanation:

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Schoolyard has an area of 3,564ft.² the section that is in the shape of a triangle is just for picnic table and what is the area
asambeis [7]

Answer:

The area of the section for the picnic tables is 1,188\ ft^{2}

Step-by-step explanation:

we know that

The area of the schoolyard is equal to the area of a rectangle plus the area of a triangle

so

3,564=44*(2x-x)+\frac{1}{2}(2x-x)*44\\ \\3,564=44x+22x\\\\3,564= 66x\\ \\x=54\ ft

The area of the triangle is equal to

22x=22*54=1,188\ ft^{2}

6 0
3 years ago
Y=4, -4y + 5 evaluate it please​
Shtirlitz [24]

Answer:

Step-by-step explanation:

=

4

−

4

+

5

=

9

−

4

8 0
2 years ago
Please help!! Use line plot to help.
muminat
2. is 4/2 or 2     3.is 12/4 or 3    4.is 5 wholes
3 0
3 years ago
how do I find the area of an equilateral triangle given the perimeter of 60 and the height of 17.3 cm?
guajiro [1.7K]
If perimeter is 60 so the side is 60 ÷ 3 = 20

Now we can apply the area formula for triangles;

A=\frac{1}{2}.b.h\\
\\
A=\frac{1}{2}.20.17.3=10.17.3=173 \ cm^2
3 0
3 years ago
Please solve these questions for me. i am having a difficult time understanding.
s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

\angle AED = \angel BEC ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

\angle ABC = 90^{\circ}

In ΔDBC

BC=DC (Given)

So,\angle CDB=\angle DBC(Opposite angles of equal sides are equal)

So,\angle CDB=\angle DBC=x

So,\angle CDB+\angle DBC+\angle BCD = 180^{\circ} (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So,\angle CDB=\angle DBC=x = 65^{\circ}

Now,

\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90

So,\angle ABD=90-x=90-65=25^{\circ}

In ΔABD

AB = BD (Given)

So,\angle BAD=\angle BDA(Opposite angles of equal sides are equal)

So,\angle BAD=\angle BDA=y

So,\angle BAD+\angle BDA+\angle ABD = 180^{\circ}(Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0
3 years ago
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