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2 years ago

А support wire 12 yards long is attached to the top of a utility pole 10

Mathematics

1 answer:

stira [4]2 years ago

6 0

Answer:

6.6 yd

Step-by-step explanation:

$a^{2}$ + $b^{2}$ = $c^{2}$

$10^{2}$ + $b^{2}$ = $12^{2}$ Substitute a= 10 and c=12

100+ $b^{2}$ =144 Evaluate the Powers

$b^{2}$ =44 Subtract 100 on both sides.

b= $\sqrt{44}$ Square root both sides b>0 so you dont need ⊥

b=6.6 Use a calculator to evaluate.

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Find the product .-2 [7 -4 0]

Makovka662 [10]

It says find the product, so that means multiplication
-2[7 -4 0] = [-14 8 0] solving: [-14 8 0] [-3 0 5]
[42+0+70 -24+0+40 0+0+0]
[-14 8 0] * [-3 0 5] = [112 0 -30] = [112 16 0]
[112 16 0]*[6 2 1]
[112 0 -30]* [6 2 1] = [1008 114 0] [672+224+112 96+32+16 +0]
=[1008 114 0].

4 0

3 years ago

A triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis. What is the volume of the figure?

Luden [163]

Given:

A triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis.

To find:

The volume of the figure.

Solution:

Points A(0,0) and C(0,9) lies on the y-axis. Length of AC is 9 units.

Points A(0,0) and B(6,0) lies on the x-axis. Length of AB is 6 units.

If a triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis, then it will form a cone with radius 6 units and height 9 units.

Volume of a cone is

$V=\dfrac{1}{3}\pi r^2h$

where, r is radius of the base and h is vertical height of the cone.

Putting r=6 and h=9, we get

$V=\dfrac{1}{3}\pi (6)^2(9)$

$V=\pi (36)(3)$

$V=108\pi$

Therefore, the volume of the figure is $108\pi$ sq. units.

7 0

3 years ago

Find the values for a and b that would make the equality true. 4(ax^2 -5x+3)=8x^2 +bx+12

tankabanditka [31]

Answer:

a 2 and b -20

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Area for rectangle in the coordinate plane. IXL Geometry help pls !

Sidana [21]

Answer:

Step-by-step explanation:

The co-ordinates of the rectangle are:

A (8, 6)

B (-4, -10)

C (-8, -7)

D (4, 9)

The Area of Rectangle is Given by: length x breadth = AB x BC

Lengths of AB and BC can be found by distance formula

length(AB) = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} )^{2}}$ = $\sqrt{(-4-8)^{2} + (-10-6)^{2}} = 20$

Similarly,

length(BC) = 5

Area of Rectangle = AB x BC = 20 x 5 = 100 square units

5 0

3 years ago

X+2(x+3(x+4(x+5)))=153

Allushta [10]

Answer:

$x=1$

Step-by-step explanation:

Here first open the inner parentheses and use the distributive property,

$4(x+5)=4x+20\\\\(x+4(x+5))=(x+4x+20)=(5x+20)\\\\3(x+4(x+5))=3(5x+20)=15x+60\\\\(x+3(x+4(x+5)))=(x+15x+60)=16x+60\\\\2(x+3(x+4(x+5)))=2(16x+60)=32x+120\\\\x+2(x+3(x+4(x+5)))=x+32x+120=33x+120\\\\\\Hence\ x+2(x+3(x+4(x+5)))=x+32x+120=33x+120\\\\\Rightarrow 33x+120=153\\\\33x=153-120\\\\33x=33\\\\x=1$

3 0

3 years ago