Answer: No; Most students have a curfew of 9 pm or earlier
OK. I did it, and I have the solution.
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The length of the deck is (5 + 2x) .
The width of the deck is (4 + 2x) .
If the deck didn't have that big hole in the middle where the pool is,
then its area would be
(5 + 2x) · (4 + 2x) .
When you multiply that all out, you get Area = 4x² + 18x + 20
and the question tells us that the area of the whole big rectangle is 90 yds² .
So we can write
4x² + 18x + 20 = 90 .
Subtract 90 from each side: 4x² + 18x - 70 = 0
Divide each side by 2 : 2x² + 9x - 35 = 0
You can use the quadratic equation to solve that and find out that
x = 2.5 yards, and that's what the question is asking you.
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That makes the deck 10 yds high and 9 yds wide.
Total area of the whole big rectangle, (deck + pool ), = 90 yds².
Answer:
46.86
Step-by-step explanation:
a^2+b^2=c^2
30^2+36^2=c^2
2196=c^2
Square root both sides
46.86=c
Answer:
-160x+264
Step-by-step explanation:
-48+96x-112x+168
-160+264
Answer:
-8 or -1
Step-by-step explanation:
x*2+9x+8=0
(x+8)(x+1)=0
x+8=0 or x+1=0
x= -8 or x= -1
