Answer:
Step-by-step explanation:
x²+y² = 5²
3²+y² = 25
y² = 16
y = ±√16 = ±4
Since the terminal side is in quadrant IV, y = -4
sinθ = -4/5
Answer:
y + 3 = 10/11(x + 3)
Step-by-step explanation:
Given the points (-3, -3) and (8, 7), we can use these coordinates to solve for the slope of the line using the formula:
![m = \frac{y2 - y1}{x2 - x1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By2%20-%20y1%7D%7Bx2%20-%20x1%7D)
Let (x1, y1) = (-3, -3)
(x2, y2) = (8, 7)
Substitute these values into the slope formula:
![m = \frac{y2 - y1}{x2 - x1} = \frac{7 - (-3)}{8 - (-3)} = \frac{10}{11}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By2%20-%20y1%7D%7Bx2%20-%20x1%7D%20%3D%20%5Cfrac%7B7%20-%20%28-3%29%7D%7B8%20-%20%28-3%29%7D%20%3D%20%5Cfrac%7B10%7D%7B11%7D)
Thus, slope (m) = 10/11.
Next, using the slope (m) = 10/11, and one of the given points (-3, -3), we'll substitute these values into the point-slope form:
y - y1 = m(x - x1)
Let (x1, y1) = (-3, -3)
m = 10/11
y - y1 = m(x - x1)
y - (-3) = 10/11[x - (-3)]
Simplify:
y + 3 = 10/11(x + 3) this is the point-slope form.
Answer:its yhe one on the right
Step-by-step explanation:
remember to use SOH CAH TOA. THE SOLUTION THAT I GOT CAME OUT AS 15/8
Answer:
-5x-10 is the expression. the missing values would be 2 and -x i believe