<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height
The identity property of addition states that a + 0 = a
Your answer is identity property of addition.
I believe the answer would be a.
Answer: (A) randomly selected elements within each of the strata form the sample.
Step-by-step explanation:
Stratified random sampling is a random sampling technique in statistics .
- It includes the partition of the entire population into sub-parts called strata.
- The strata are formed on the basis of the characteristics shared by members .
- After the formation of strata, researcher randomly selects participants from each strata to ensure that that the participant of every group must involve in the sample to represent each character.
Hence, the correct answer is :
(A) randomly selected elements within each of the strata form the sample.
Answer:
6×(3×+1)(×-7)
Step-by-step explanation:
18×^3-120×^2-42×
=6×(3×+1)(×-7)