6x+15=27
6x/6=12/6
X=2
27-15=12
![{5}^{3} \: \times \: {5}^{ - 5}](https://tex.z-dn.net/?f=%20%7B5%7D%5E%7B3%7D%20%20%5C%3A%20%20%5Ctimes%20%20%5C%3A%20%20%7B5%7D%5E%7B%20-%205%7D%20)
- We first compute the product.
![{5}^{ - 2}](https://tex.z-dn.net/?f=%20%7B5%7D%5E%7B%20-%202%7D%20)
- We can transform the product into positive if we use this formula:
![\boxed{ {a}^{ - n} \: = \: \frac{1}{ {a}^{n} } }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%7Ba%7D%5E%7B%20-%20n%7D%20%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%5Cfrac%7B1%7D%7B%20%7Ba%7D%5E%7Bn%7D%20%7D%20%7D)
<h3>We apply it:</h3>
![{5}^{ - 2} \: = \: \boxed{ \bold{\frac{1}{ {5}^{2} } }}](https://tex.z-dn.net/?f=%20%7B5%7D%5E%7B%20-%202%7D%20%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%20%5Cboxed%7B%20%5Cbold%7B%5Cfrac%7B1%7D%7B%20%7B5%7D%5E%7B2%7D%20%7D%20%7D%7D)
<h2>Answer: </h2>
![\text{Option C.} \: \boxed{ \bold{\frac{1}{ {5}^{2} } }}](https://tex.z-dn.net/?f=%5Ctext%7BOption%20C.%7D%20%5C%3A%20%20%5Cboxed%7B%20%20%5Cbold%7B%5Cfrac%7B1%7D%7B%20%7B5%7D%5E%7B2%7D%20%7D%20%7D%7D)
<h3><em><u>MissSpanish</u></em></h3>
Answer:
13.8
Step-by-step explanation:
tan Q = <u>opposite </u> = <u>40</u>
adjacent x
Tan 71 = <u>40</u> x tan 71 = 40
<u> x tan 71</u> = <u> 40 </u>
tan 71 tan 71
x = <u> 40 </u> = 13.7731 = 13.8 (rounded to the nearest tenth)
tan 71
Answer:
5 and 6 or 25 and 36
Step-by-step explanation:
Just ADD 1 +3 then subtract it from 1.4 inch