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lina2011 [118]
2 years ago
14

Elsa tries to solve the following equation, and determines there is no solution. is she correct? explain. log2x = log2(3x 5) 4

Mathematics
1 answer:
SOVA2 [1]2 years ago
7 0

Elsa's claim that the logarithmic equation \log_2(x) = \log_2(3x+5)+4 has no solution is true

<h3>How to determine the true statement?</h3>

The logarithmic equation is given as:

\log_2(x) = \log_2(3x+5)+4

Express 4 as a logarithm expression

\log_2(x) = \log_2(3x+5)+\log_2(16)

Apply the rule of logarithm

\log_2(x) = \log_2(16 *(3x+5))

Cancel out the common base

x = 16 *(3x+5)

Expand

x = 48x + 80

Collect like terms

x - 48x = 80

This gives

-47x = 80

Divide both sides by -47

x =-80/47

When the value of x is negative, then the logarithmic equation has no solution

Hence, Elsa's claim is true

Read more about logarithmic equations at:

brainly.com/question/237321

#SPJ4

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Answer:  The answer is \textup{M}+\textup{H}\leq 10~~\textup{and}4\textup{M}+7\textup{H}\leq 90.


Step-by-step explanation: Given that a school wants to put on a dance recital. The programs of Middle school dancer will be short of 4 minutes each and programmes of High school performers will be long of 7 minutes each.

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