What are you saying lol. Most of us are English
A two-digit number is twice the sum of its digit. If the tens digit is 7 less than the unit digit, find the number.
Let x= the unit digit
Then y= the tens digit
<span>And 10y+x= the number
</span>x+y= the sum of the digits
<span>Now we are told that 10y+x=2(x+y) ------1st equation </span>
<span>We are also told that y=x-7 ----------- 2nd Equation </span>
<span>So our equations to solve are: </span>
(1) 10y+x=2(x+y)
<span>(2) y=x-7
</span>
Hope it helps
One expression could be.... Nine times 4 plus five equals forty one. ALSO... Eight times eight equals sixty four then subtract twenty four equals forty one
Answer:
Step-by-step explanation:
Given is a trignometric equation in x, as
TO make it in one trig ratio, we can replace sin2x as 2sinx cosx
WE get now
Principal solution is 
x = ±π/2 + 2kπ, where k is any integer or
x=±pi/6 +k pi, where k is any integer.
General solution is
