If i did not that would he just like that one time when 373848 people are gone so they are just saying something AC
Check the picture below.
so by graphing those two, we get that little section in gray as you see there, now, x = 6 is a vertical line, so we'll have to put the equations in y-terms and this is a washer, so we'll use the washer method.

the way I get the radii is by using the "area under the curve" way, namely, I use it to get R² once and again to get r² and using each time the axis of rotation as one of my functions, in this case the axis of rotation will be f(x), and to get R² will use the "farthest from the axis of rotation" radius, and for r² the "closest to the axis of rotation".

now, both lines if do an equation on where they meet or where one equals the other, we'd get the values for y = 0 and y = 1, not surprisingly in the picture.
![\displaystyle\pi \int_0^1\left( 3y-3y^2-\cfrac{y^2}{16}+\cfrac{y^4}{16} \right)dy\implies \pi \left( \left. \cfrac{3y^2}{2} \right]_0^1-\left. y^3\cfrac{}{} \right]_0^1-\left. \cfrac{y^3}{48}\right]_0^1+\left. \cfrac{y^5}{80} \right]_0^1 \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{59\pi }{120}~\hfill](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cpi%20%5Cint_0%5E1%5Cleft%28%203y-3y%5E2-%5Ccfrac%7By%5E2%7D%7B16%7D%2B%5Ccfrac%7By%5E4%7D%7B16%7D%20%5Cright%29dy%5Cimplies%20%5Cpi%20%5Cleft%28%20%5Cleft.%20%5Ccfrac%7B3y%5E2%7D%7B2%7D%20%5Cright%5D_0%5E1-%5Cleft.%20y%5E3%5Ccfrac%7B%7D%7B%7D%20%5Cright%5D_0%5E1-%5Cleft.%20%5Ccfrac%7By%5E3%7D%7B48%7D%5Cright%5D_0%5E1%2B%5Cleft.%20%5Ccfrac%7By%5E5%7D%7B80%7D%20%5Cright%5D_0%5E1%20%5Cright%29%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Ccfrac%7B59%5Cpi%20%7D%7B120%7D~%5Chfill)
Answer:
59
Step-by-step explanation:
you do
80 -7= 73
73-7=66
66-7=59
sorry i dont have answered
Answer look it up learn to add and subtract radical expansions
Step-by-step explanation: