Solve 6^x+2 = 10 for x using the change of base formula

Mathematics

1 answer:

pashok25 [27]1 year ago

3 0

Answer:

$x\approx-0.7149$

Step-by-step explanation:

$\displaystyle 6^{x+2}=10\\\\\log_6(6^{x+2})=\log_6(10)\\\\x+2=\frac{\log(10)}{\log(6)}\\\\x+2\approx1.2851\\\\x\approx-0.7149$

Recall that the change of base formula is $\displaystyle \log_a(b)=\frac{\log(b)}{\log(a)}$

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