Step-by-step explanation:
37x + 41y = 70 --- R¹
41x + 37y = 86 --- R²
R¹ + R² : 78x + 78y = 156
78(x + y) = 156
x + y = 2 --- R³
R¹ - R² : -4x + 4y = -16
4(y - x) = -16
y - x = -4 --- R⁴
R³ + R⁴ : 2y = -2
y = -1
R³ - R⁴ : -2x = -6
x = 3
Answer:
everyone will have 15 dogs each
Step-by-step explanation:
dogs:
1+2+3+4+5=15
humans:
54+38+3+1+4=100
100x15=1500 <<<how many dogs there are in total
1500%100=15 <<<how many each person will get if u add all the dogs and divide them evenly for each person
Answer: Yes
Step-by-step explanation:
1. Substitute 1 for x
2. 6 times 1 is 6 plus 2 is 8
3.8 is equal to or greater than 8
The equation that we can create from this situation is:
i = (190 – 5 x) * (29 + x)
where i is the income and x is the increase in daily rate
Expanding the equation:
i = 5510 + 190x – 145x - 5x^2
i = -5x^2 + 45x + 5510
Taking the 1st derivative:
di/dx = -10x +45
Set to zero to get the maxima:
-10x + 45 = 0
x = 4.5
So the cars should be rented at:
29 + x = 33.5 dollars per day
The maximum income is:
i = (190 – 5*4.5) * (33.5)
i = 5,611.25 dollars
