Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
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A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.
Answer:
x = -2/5
y = 12/5
Step-by-step explanation:
Substitution method;
-2x + 3y = 8 -----------(i)
x + y =2 -----------(ii)
x = 2 - y
substitute the value of x in equ (i)
(-2)* (2-y) + 3y = 8
-4 + 2y + 3y = 8
5y = 8 + 4
y = 12/5
substitute the value of y in equ (ii)
x + 12/5 = 2
x = 2 - 12/5
= 2*5/1*5 - 12/5
= 10 -12/5 = -2/5
Ans: x = -2/5
y = 12/5
elimination method:
-2x + 3y = 8 -----------(i)
x + y =2 -----------(ii)
(i) ====> -2x + 3y = 8
multiply equ (ii) by 2 ====> <u> 2x + 2y = 4</u>
add (i) and (ii) 5y = 12
y = 12/5
Substitute in equ (ii)
x + 12/5 = 2
x = 2 - 12/5
= 2*5/1*5 - 12/5
= 10 -12/5 = -2/5
Ans: x = -2/5
y = 12/5
You do the reverse and divide the 2 values to find out the last one
72/9 = 8
Do you get it?
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