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Ber [7]
3 years ago
13

(fx) =

6%29" id="TexFormula1" title="(fx) = \sqrt[3]{ - 3x + 3} find f( - 13.6)" alt="(fx) = \sqrt[3]{ - 3x + 3} find f( - 13.6)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
never [62]3 years ago
4 0
f(x)=\sqrt[3]{-3x+3}\\\\substitute\ the\ value\ of\ x\ to\ the\ equation:\\\\f(-13.6)=\sqrt[3]{-3(-13.6)+3}=\sqrt[3]{40.8+3}=\sqrt[3]{43.8}\approx3.525
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How does this work?????
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Answer:

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Roman55 [17]
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3 years ago
Please help on this. I am confused.
neonofarm [45]
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3 0
3 years ago
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lions [1.4K]

Answer:

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Hence, (x - 5) ≥ 0

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<em>Note: Thanks rani</em>

3 0
3 years ago
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