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rusak2 [61]
3 years ago
5

Bailey writes the expression g2 + 14g + 40 to represent the area of a planned school garden in square feet. If g = 5, what are t

he dimensions of the school garden?
20 feet by 2 feet
10 feet by 4 feet
12 feet by 7 feet
15 feet by 9 feet
Mathematics
1 answer:
ikadub [295]3 years ago
5 0
The expression is A=g^2 + 14g + 40.
D=14^2-4\cdot 40=196-160=36 \\  \sqrt{D}=6  \\ q_{1,2}= \dfrac{-14\pm 6}{2}  =-4,-10.
Then A=g^2 + 14g + 40=(g+4)(g+10).
The width is g+4, the length is g+10.
When g=5, 
g+4=9 ft and g+10=15 ft.
Answer: correct choice is D.

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Mila graphs the point A
melamori03 [73]
Answers:
B. <span>The x-coordinate of point A is 5.
</span>E. <span>Point A is on the x-axis.
</span>
Explanation:
Any point drawn on the coordinates has the general notation of (x,y).
The given point is (5,0). This means that:
The x-coordinate of the point is 5
The y-coordinate of the point is 0

Now, let's check the place of this point.
The x-coordinate of the point is 5. This means that we will move 5 points to the right of the origin on the x-axis
The y-coordinate of the point is 0. This means that we will not move along the y-axis which means that the point stays on the x-axis.

Now, comparing the deduced results with the given choices, we will find that the correct choices are B and E

Hope this helps :)
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3 years ago
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Ierofanga [76]

Step-by-step explanation: Devide and do it yourself.....

3 0
3 years ago
Please answer this question
zimovet [89]

Answer:

The answer is 030

Step-by-step explanation:

I am unable to transmit my working but don't forget to write the bearing as 030 not 30

6 0
3 years ago
Anyone know how to find the area of an equilateral triangle circumscribed about a circle, given the radius of the circle?
tia_tia [17]
Warning: This might be rough...
First draw it out. Label the angles at the corners of the triangle 60 (definition of equilateral triangles). Now draw a line from the center of the circle to the corner, splitting the corner in half. Label this line R and a corner as 30 degrees. No to find the height of this triangle, you do rsin(30). The base of this triangle is 2rcos(30). Now find the area of this mini triangle (rsin(30)*2rcos(30)/2=r/2*rsqrt(3)/2=r^2sqrt(3)/4). Now multiply this by 3 because you have 3 mini triangles... to get...
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8 0
3 years ago
I need help for brainliest
devlian [24]

Answer:

<h2><u><em>46 cm²</em></u></h2>

Step-by-step explanation

the figure is composed of a square with an isosceles right triangle inside, we find the area of ​​the square and we take away the area of ​​the triangle.

Triangle area = lxl, right-angled triangle area side by side divided by two.

  • square area

8 * 8 = 64cm²

  • Triangle area

6 * 6 : 2 = 18 cm²

Area of the shaded region

64 - 18 = 46 cm²

7 0
2 years ago
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