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melomori [17]
3 years ago
8

Question 1: Please help, look at the picture below.

Mathematics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

1.98

Step-by-step explanation:

The triangle in the figure is a right triangle, which has a 90 degrees angle.

The side opposite to the right angle is called hypothenuse, and it is the longest side of the triangle.

For a right triangle, the following relationship exists between angles and sides:

sin \theta = \frac{opposite}{hypothenuse} (1)

cos \theta=\frac{adjacent}{hypotenuse}

where \theta is any of the other 2 angles in the triangle, and opposite means "side opposite to the angle" and adjacent means "side adjacent to the angle".

In this problem, we know that the angle at D is

\theta=26^{\circ}

We also know that the hypothenuse is

hypothenuse=DF=4.5

Therefore, in order to measure EF, we can use eq.(1). We find:

sin \theta = \frac{EF}{DF}\\EF=DF sin \theta = (4.5)(sin 26^{\circ})=1.98

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Supposed that over a period of several years the average number of deaths from a certain noncontagious disease has been 5. If th
jonny [76]

Answer:

a) 0.00673

b)0.9596

Step-by-step explanation:

Let be X the random variable : ''Number of deaths from this disease''

X ~ P(λt)

Where λ is number of events per unit time and λt is number of events over time period t

In our exercise t = 1 year

λ : lambda

The probability function for X is :

P(X=x)=\frac{e^{-( lambda).t}.(lambda.t)^{x} }{x!}

x ≥ 0

a)

P(X=0) =\frac{e^{-5}(5)^{0} }{0!}=e^{-5}=0.00673

b)

P(X\geq 2)=1-P(X

P(X\geq 2)=1-[e^{-5}+\frac{e^{-5}.(5)^1}{1!}}]=1-[e^{-5}+5(e^{-5})]=1-6(e^{-5})=0.9596

8 0
3 years ago
What can I do to get y alone on one side of the equation
Anika [276]

Answer:

All you have to do is subtract or add the numbers that are not the variable, y, on both sides to get the variable, y, on one side of the equation. Then, if there is a number in front of it, you must divide that number on both sides.

Step-by-step explanation:

All you have to do is subtract or add the numbers that are not the variable, y, on both sides to get the variable, y, on one side of the equation. Then, if there is a number in front of it, you must divide that number on both sides.

3 0
4 years ago
Read 2 more answers
Help me please :33 :ppp
Marrrta [24]

Answer:

your speed is 8.1

Step-by-step explanation:

17.5-9.4=8.1

8 0
3 years ago
It rained 0.8 inches on Monday. On Tuesday, it rained 0.34 inches less than on Monday. How much did it rain on Tuesday?
kifflom [539]
Ion even kno, i’m just doin this so i can get help
7 0
3 years ago
Please help me!!! I don't understand how to solve it(((
olganol [36]
\sqrt{( \sqrt{7-2 \sqrt{10} }+ \sqrt{2} )*2 \sqrt{5}  }=  \\ = \sqrt{( \sqrt{2-2 \sqrt{2*5}+5 }+ \sqrt{2} )*2 \sqrt{5}  }= \\  \sqrt{( \sqrt{( \sqrt{2}- \sqrt{5})^{2}    }+ \sqrt{2} )*2 \sqrt{5}  }= \\  \sqrt{(  \sqrt{5}-  \sqrt{2} + \sqrt{2} )*2 \sqrt{5}  }= \\ \sqrt{  \sqrt{5} *2 \sqrt{5}  }=   \\  \sqrt{2*5} = \sqrt{10}
HAVE A NICE DAY!! ^^
4 0
3 years ago
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