The trip there is 58.5$ and the trip back is 63$. 63-58.5= 4.50. Which makes the answer B
check the transformation template below, hmmm so to get the graph of "y" move to the right by 1 unit, we can simply make C = -1.
now, the x-intercept is simply where the graph touches the x-axis, and when that happens y = 0, so
![\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad a^{log_a x}=x\leftarrow \textit{let's use this rule} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{y}{0}~~ = ~~\log_2(x-1)\implies 2^0=2^{\log_2(x-1)}\implies 2^0=x-1 \\\\\\ 1=x-1\implies 2=x~\hspace{10em}\stackrel{x-intercept}{(2~~,~~0)}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7BLogarithm%20Cancellation%20Rules%7D%20%5C%5C%5C%5C%20log_a%20a%5Ex%20%3D%20x%5Cqquad%20%5Cqquad%20a%5E%7Blog_a%20x%7D%3Dx%5Cleftarrow%20%5Ctextit%7Blet%27s%20use%20this%20rule%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7By%7D%7B0%7D~~%20%3D%20~~%5Clog_2%28x-1%29%5Cimplies%202%5E0%3D2%5E%7B%5Clog_2%28x-1%29%7D%5Cimplies%202%5E0%3Dx-1%20%5C%5C%5C%5C%5C%5C%201%3Dx-1%5Cimplies%202%3Dx~%5Chspace%7B10em%7D%5Cstackrel%7Bx-intercept%7D%7B%282~~%2C~~0%29%7D)
Answer:
218
Step-by-step explanation:
43 - w = 175
__________
To calculate the w, you need to add 43 to 175
w = 175 + 43
w = 218
Answer:
4
Step-by-step explanation:
Recall a linear function, is a line on a graph made up of an infinite amount of points which satisfy the relationship. That means at x=3 there is a specific point on the line with an output. The value of a function at x=3 asks, what is the output y value for the input x value?
To find it, we locate 3 on the x-axis. We draw a vertical line directly to the line following the grid line. We mark the point on the line. We then draw a horizontal line directly to the y-axis following the grid line. The point we hit on the y-axis is the value of the function.
Here it is 4.
2X^2 + 4y = 2 * -2^2 + 4 * 3
Your answer is 4.
If this is incorrect, then I am sorry.
