1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rainbow [258]
2 years ago
7

Ansley drove 8.7 miles to the park then she drove 12.43 miles to the museum how many miles did Ansley drive in all

Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
5 0
Answer: 21.13 miles

Explanation: The question asks “drive in all”. They gave you the miles driven, which is 8.7 and 12.43. If you add them together, you will get 21.13 miles.
Zanzabum2 years ago
4 0

Answer:

8.7 + 12.43 = 21.13

Why did we add?

"In all" indicates addition, therefore giving us 2 values to add together, and that is why we added the two given values.

You might be interested in
Find the equivalent fraction<br> 3/7 = ?/21
vlabodo [156]
The equivalent fraction for 3/7 is 9/21
6 0
3 years ago
Read 2 more answers
Holly missed 7 of 180 days this year. Approximately what percent of school days was Holly in school?
Sphinxa [80]
Hi There!

Since there are 180 school days and Holly missed 7 then she attended \frac{173}{180} days.

So, to find out the percent of school days she attended school you have to divide  173/180, 173 represents school days she attended or numerator, and 180 represents total school days the denominator. Once you divide 173/180 you should get  0.<span>96111111111, but if you round it, the answer will be 96%.

Steps

1. Divide 173/180= 0.</span>96111111111<span>

2. Round you're answer  0.</span><span>96111111111
</span>

Final Answer- Holly attended 96% percent of school days.

Hope This Helps:)
5 0
3 years ago
In how many distinguishable ways can you arrange the letters in the word CONNECTICUT? *
borishaifa [10]

Answer:

The number of distinguishable arrangements are 1,663,200.

Step-by-step explanation:

The word is: CONNECTICUT

The number of ways to arrange a word when no conditions are applied is:

\frac{n!}{k_{1}!\cdot k_{2}!\cdot k_{3}!...\cdot k_{n}!}

Here <em>k</em> is the number of times a word is repeated.

In the word CONNECTICUT there are:

3 Cs

2 Ns

2 Ts

And there are a total of <em>n</em> = 11 letters

So, the number of distinguishable arrangements are:

\frac{n!}{k_{1}!\cdot k_{2}!\cdot k_{3}!...\cdot k_{n}!}=\frac{11!}{3!\times 2!\times 2!}

                     =\frac{39916800}{6\times 2\times 2}\\\\=1663200

Thus, the number of distinguishable arrangements are 1,663,200.

7 0
3 years ago
Need some figuring out which sentence has one solution,no solution, and infinite solution.
dolphi86 [110]

Answer:

the second one

Step-by-step explanation:

4 0
3 years ago
Number 29 please I just need to know how to set it up
scoundrel [369]

Answer: sorry idk

Step-by-step explanation:

3 0
4 years ago
Other questions:
  • If (−7, m) is on a circle with center c(3, 5) and radius 10, what is the value of m? m = 5 m equals negative five plus two squar
    15·1 answer
  • Can someone help me with my math problem pls my teacher is on my back about this
    10·2 answers
  • Use the Quadratic Formula to solve the equation 4x2+1=8x.
    10·1 answer
  • 8^(3x-1)=2^8 <br><br>Solve for x 
    13·2 answers
  • A rectangular prism with a volume of 5 cubic units is filled with cubes with side lengths of 1/3 unit how many unit cubes does i
    9·1 answer
  • Parallelogram DEFG is transformed to parallelogram VSTU.
    10·2 answers
  • Two men p and q set off from a base camp r prospecting for o,p moves 40km on a bearing 205 degree and q moves 30km on a bearing
    6·1 answer
  • Write three integers that do not ali have the same sign that have a sum<br> of -20.
    15·1 answer
  • graph the line that passes through the points (-3,-7) and (-2,-7) and determine the equation of the line
    9·1 answer
  • Simplify the expression<br><br> -6 +4x+ 9 -2x
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!