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3 years ago

Factor the quadratic equation x2 – 19x + 84 = 0 and find the zeros of the function.

Mathematics

1 answer:

Stells [14]3 years ago

7 0

x-12)=0

x-12+12=0+12

x=12

Solve:

(x-7) = 0

x-7+7 = 0+7

x=7

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Help please!!! I don't understand

zaharov [31]

$\left|x-\dfrac 12\right| = 3\dfrac 23\\\\\\\implies \left|x- \dfrac 12 \right| = \dfrac{11}3\\\\\\\implies x-\dfrac 12 = \dfrac{11}3 ~~~~~~~~~ \text{or}~~~~~~~ x - \dfrac 12 = - \dfrac {11}3\\\\\\\implies 2x -1 = \dfrac{22}3 ~~~~~~~~ \text{or}~~~~~~~~2x-1 =-\dfrac{22}3\\$

$\implies x =\dfrac 12\left(\dfrac{22}3 +1 \right) ~~ \text{or}~~~~~~~~ x = \dfrac 12 \left(1-\dfrac{22}3\right)}\\\\\\\implies x = \dfrac{25}6~~~~~~~~~~~~~~~ \text{or}~~~~~~~~ x=-\dfrac{19}6\\\\\\\implies x = 4\dfrac 16 ~~~~~~~~~~~~~~~ \text{or}~~~~~~~~x = -3\dfrac16$

6 0

2 years ago

A grasshopper jumps off a tree stump. The height, in feet, of the grasshopper above the ground after t seconds is modeled by the

Monica [59]

The height, in feet, of the grasshopper above the ground after t seconds is modeled by the function , which is

$h(t) =-t^2+\frac{4}{3}t+ \frac{1}{4}$

When the grasshopper land on the ground,

$h(t)=0$

that is,

$-t^2+\frac{4}{3}t+ \frac{1}{4}=0$

Multiplying whole equation by 12 to get rid of denominators 3 and 4

$-12t^2+16t +3=0$

$(3-2t)(6t+1)=0 \\ 3-2t=0 , 6t+1=0 \\ t= \frac{3}{2} , \frac{-1}{6}$

And time cant be negative, so the correct option is

$t = \frac{3}{2}=1.5 seconds$

Correct option is C .

0 0

4 years ago

I need help uys nowwww

kaheart [24]

Answer:

First we find the value of x,

x ≥ -4

Step-by-step explanation:

3x+7 ≥ -5

3x ≥ -5 -7

3x ≥ -12

x ≥ -4

Now to graph this inequality, consider number line.

numbers greater than and equal to -4 are -3,-2,-1,0 and so on.

Note that in solution -4 is included so in graphing we use dot (filled circle).

7 0

3 years ago

Suppose that A, B, and C are invertible matrices of the same

STALIN [3.7K]

Answer:

Step-by-step explanation:

Given that t A, B, and C are invertible matrices of the same

size.

To pr that $(ABC)^{-1} = C^{-1}B^{-1}A^{-1}.$

to pr that $( ABC) (C^{-1}B^{-1}A^{-1})=e$

LS= $( AB(C (C^{-1})B^{-1}A^{-1})\\=ABIB^{-1}A^{-1})\\=A(BB^{-1})A^{-1})\\=AA^{-1})\\=I$

Thus proved

8 0

3 years ago

Of 400 college students, 115 are enrolled in math, 225 are enrolled in English, and 55 are enrolled in both. If a student is sel

NikAS [45]

115 are enrolled in Math, of which 55 are also enrolled in English. So, 115-55, or 60 are enrolled in math alone. 225 are enrolled in English, so 175 are not. Then, 175+60/400=.5875 probability that student is not enrolled in English or is enrolled in math. ☺☺☺☺

6 0

3 years ago