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Illusion [34]
3 years ago
6

Sally bought 124 sheets of stickers. Each sheet had 14 stickers. She gave away 204 stickers to her family and friends on Christm

as. How many stickers does Sally have remaining?
Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer:

Sally has 1,532 stickers remaining.

Step-by-step explanation:

First, you have to determine the total amount of stickers Sally bought by multiplying the number of sheets she bought for the number of stickers in each sheet:

124*14=1,736

Now, you have to subtract the number of stickers Sally gave away to her family and friends from the total amount of stickers she bought:

1,736-204=1,532

According to this, the answer is that Sally has 1,532 stickers remaining.

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A random sample of 49 statistics examinations was taken. the average score, in the sample, was 84 with a variance of 12.25. the
tester [92]

Since in this case we are only using the variance of the sample and not the variance of the real population, therefore we use the t statistic. The formula for the confidence interval is:

<span>CI = X ± t * s / sqrt(n)                      ---> 1</span>

Where,

X = the sample mean = 84

t = the t score which is obtained in the standard distribution tables at 95% confidence level

s = sample variance = 12.25

n = number of samples = 49

From the table at 95% confidence interval and degrees of freedom of 48 (DOF = n -1), the value of t is around:

t = 1.68

 

Therefore substituting the given values to equation 1:

CI = 84 ± 1.68 * 12.25 / sqrt(49)

CI = 84 ± 2.94

CI = 81.06, 86.94

 

<span>Therefore at 95% confidence level, the scores is from 81 to 87.</span>

6 0
4 years ago
to find the perimeter of the rectangle you can see the formula P=21+2W. find the perimeter P of a rectangle whose length L is 10
Olin [163]

Answer:

rectangle, the distance around the outside of the rectangle is known as perimeter. A rectangle is 2-dimensional; however, perimeter is 1-dimensional and is measured in linear units such as feet or meter etc.

The perimeter of a rectangle is the total length of all the four sides.

Perimeter of rectangle = 2L + 2W.

Example 1: Rectangle has the length 13 cm and width 8 cm. solve for perimeter of rectangle.

Solution:

Given that:

Length (l) = 13 cm

Width (w) = 8 cm

Perimeter of the rectangle = 2(l + w) units

P = 2(13 + 8)

P = 2 (21)

P = 42

Thus, the perimeter of the rectangle is 42 cm.

Example 2: If a rectangle's length is 2x + 1 and its width is 2x – 1. If its area is 15 cm2, what are the rectangle's dimensions and what is its perimeter?

Solution:

We know that the dimensions of the rectangle in terms of x:

 l = 2x + 1

w = 2x – 1

Since the area of a rectangle is given by:

A = l * w

We can substitute the expressions for length and width into the equation for area in order to determine the value of x.

A = l * w

15 = (2x + 1) (2x -1)

15 = 4x2 – 1

16 = 4x2

x = ±2

 

 Note that the value of x must be positive and therefore in our case, the value of x is 2. And now we have:

l = 5 cm

w = 3 cm

Therefore, the dimensions are 5cm and 3cm.

Now, substituting these values in the formula for perimeter, we will get

P = 2l + 2w

P = 2(5)+2(3)

P = 10+6

P = 16 cm

Example 3: Find the area and the perimeter of a rectangle whose length is 24 m and width is 12m?

Solution:

Given that:

length = L = 24m

width = W = 12m

Area of a rectangle:

A = L × W

A = 24 × 12

A = 188 m2

Perimeter of a rectangle:

P = 2L + 2W

P = 2(24) + 2(12)

P = 48 + 24

P = 72 m

Example 4: Find the area and perimeter of a rectangle whose breadth is 4 cm and the height 3 cm.

Solution:

Area = b×h = 4×3 = 12 cm2.

Perimeter = 2(b) + 2(h) = 2(4) + 2(3) = 8 + 6 = 14.

Example 5: Calculate the perimeter of the rectangle whose length is 18cm and breadth 7cm

Solution:

Given that:

L = 18 cm

B = 7 cm

Perimeter of rectangle = 2(length + breadth)

P = 2 (L + B)

P = 2 (18 + 7)

P = 50 cm

Example 6: Find the perimeter of rectangle whose length is 6 inches and width is 4 inches.

Solution:

P = 2(L + B)

P = 2(6 + 4)

P = 20 in

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Solution:

Given that:

Length = L = 100m

Width = W = 50m

Rounds = 5

Time per 100m = 5minutes.

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P = 2 L + 2 W.

P = 2 × 100 + 2 × 50

P = 200 + 100

P = 300 m

Total distance walked = 5 × Perimeter of the park.

= 5 × 300

= 1500 meters

Total time taken = Total distance walked × time taken to walk 1m.

= 1500 × 5/100

= 75minutes or 1hr 15minutes

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Answer:

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I am Lyosha [343]

Answer:

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