2 years ago

Write the quadratic function f(x) = (3-x)2 in standard form.

Mathematics

1 answer:

Nitella [24]2 years ago

6 0

Answer:

$y = - 2x + 6$

Step-by-step explanation:

$since \: f(x) = y \\$

then the equation reads:

$y = (3 - x)2 \\ y = 6 - 2x \\$

The standard form of an quadratic function is:

$y = mx + c \\$

So the answer is:

$y = mx + c \\ y = - 2x + 6$

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I barely ask questions but I really need help with #3 and a little with 4. On number four I got 1 1/20 which doesn’t seem right.

uranmaximum [27]

Let r, g and b represent red, green and blue.

r+g+b = 74

r=g-1

b=r+g

Again, r+g+b = 74. Let's substitutte r+g for b: r+g+(r+g) = 74.

Next, let's eliminate r. Use r=g-1. Then g-1 + g + g-1 + g = 74

Combining the g terms, 4g - 2 = 74 => 4g = 76 => g = 19

Recall that r=g-1
and
b=r+g

Find r. If r=g-1, and g=19, then r = 19-1=18

Find b: b = r+g = 18+19=37

So there are 37 blue candies, 18 red candies and 19 green candies.

Check: 37+18+19=74 ??? Yes.

8 0

3 years ago

In math, a statement that shows that two expressions are equal.

adoni [48]

Answer:

= this is that two expression two equal numbers

8 0

1 year ago

Solve the system using substitution x+5y=0 3y+2x=-21

Crazy boy [7]

Answer:

$\left \{ {{x = -15} \atop {y=3}} \right.$

Step-by-step explanation:

$\left \{ {{x + 5y = 0} (1) \atop {3y + 2x = -21}(2)} \right. \left \{ {{x = -5y} \atop {3y + 2x = -21}} \right. \left \{ {{x = -5y} \atop {3y + 2*(-5y) = -21}} \right. \left \{ {{x = -5y} \atop {3y - 10y = -21}} \right. \\ \left \{ {{x = -5y } \atop {-7y = -21}} \right. \left \{ {{x = -5y} \atop {y= 3 }} \right. \left \{ {{x = -5 * 3} \atop {y=3}} \right.=> \left \{ {{x=-15} \atop {y=3}} \right.$